Answer:
The second experiment (reversible path) does more work
Explanation:
Step 1:
A piston confines 0.200 mol Ne(g) in 1.20L at 25 degree °C
<em>(a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm</em>
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Irreversible path: w =-Pex*ΔV
⇒ with Pex = 1.00 atm
⇒ with ΔV = 1.20 L
W = -(1.00 atm) * 1.20 L
W = -1.20L*atm *101.325 J /1 L*atm = -121.59 J
<em>(b) The gas is allowed to expand reversibly and isothermally to the same final volume.</em>
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W = -nRTln(Vfinal/Vinitial)
⇒ with n = the number of moles = 0.200
⇒ with R = gas constant = 8.3145 J/K*mol
⇒ with T = 298 Kelvin
⇒ with Vfinal/Vinitial = 2.40/1.20 = 2
W = -(0.200mol) * 8.3145 J/K*mol *298K *ln(2.4/1.2)
W = -343.5 J
The second experiment (reversible path) does more work
When a solute is dissolved in a solvent the solute raises the boiling point of the solvent. The boiling point of a liquid (a solvent) will be higher when another compound (solute) is added, such that a solution has a higher boiling point than a pure solvent. This takes place when a non-volatile solute, such as a salt, is added to a pure solvent such as water.
Answer:
The collision theory is defined as the rate of a reaction is proportional to the rate of reactant collisions.
Explanation:
The reacting species should collide with orientation that allows contract between the atoms that will become bonds together in the product.
The collision occurs with adequate energy to permit mutual penetration of the reacting species. The two physical factors based on the orientation and energy of collision, the following reaction with carbon monoxide with oxygen is considered.
2CO(g) + O2(g) → 2CO2 (g)
After collision between the carbon monoxide and oxygen the reaction is
CO(g) + O2(g) → CO2 (g) + O(g)
Based on the theories of chemical reaction the molecules collide with sufficient amount of energy an activated complex is formed.
Yes it is but I have to check so wait
