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d1i1m1o1n [39]
4 years ago
15

Try it

Mathematics
2 answers:
8090 [49]4 years ago
8 0

Answer:

Step-by-step explanation:

Perimeter of equilateral triangle = 15x³ + 33x⁵

side = Perimeter/3

=\frac{15x^{3}+33x^{5}}{3}=\frac{15x^{3}}{3}+\frac{33x^{5}}{3}\\\\=5x^{3}+11x^{5}feet

matrenka [14]4 years ago
6 0

Answer:

is D

Step-by-step explanation:

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Using the quadratic formula, which of the following are the zeros of the
Nana76 [90]

Answer:

y=x2-X-5 is zero of quadratic equation

8 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 < T &l
NeX [460]

Answer:

N(T(t))=432t^2-374.4t-118.88

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

N(T)=27T^2-180T+100

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

T(t)=4t+1.6

We need to find the composite function N(T(t)).

N(T(t))=N(4t+1.6)

N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100

N(T(t))=432t^2+345.6t+69.12-720t-288+100

N(T(t))=432t^2-374.4t-118.88

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88

N(T(5.8))=14532.48-2290.4

N(T(5.8))=12242.08

N(T(5.8))\approx 12242

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0
4 years ago
How to solve this 3/10÷1/2
Citrus2011 [14]
3/5 is your answer. Hope this helps. There’s a picture attached with the work.

8 0
3 years ago
(15y^0 x^-3 z^2/ 3x^3 y^7 z^1/2)^2
ArbitrLikvidat [17]
Hello! For this you are just going to do this step by step, and remember to use PEMDAS. That is the order in which you should do the math. The abbreviation stands for  Parenthesis, exponents, multiplication, division, addition and subtraction. So lets get started!
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Hope this helps!! If you need any more help or further explanation just let me know!! :)
 

6 0
4 years ago
How do you use equivalent rates in the real world?
kotykmax [81]
Cross multiplication
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7 0
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