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svetoff [14.1K]
3 years ago
7

What is the relationship among proportional relationships lines, rates of change, and slope?

Mathematics
2 answers:
tia_tia [17]3 years ago
5 0

First of all, let's define some concepts. In mathematics, proportional relationships happen when two values always change by the same multiple. That is, when one doubles, the other doubles as well. So, you can always reduce a proportional relationship to the same equation as follows:

y=kx \\ where \ k \ is \ the \ proportionality \ constant

This constant is also the <em>slope </em>of the straight line.

On the other hand, the average rate of change between any two points (x_{1},f(x_{1}) \ and \ (x_{2},f(x_{2}) is the slope of the line through the two points. The line through the two points is called the secant line and its slope is denoted as m_{sec}, so:

ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}} \\ \\ \therefore ARC=\frac{Change \ in \ y}{Change \ in \ x}=m_{sec}

Finally, The slope of a nonvertical line is the number of units the line rises (or falls) vertically for each unit of horizontal change from left to right, so:

Slope=\frac{change \ in \ y}{change \ in \ x}=\frac{rise}{run}

<em>So, we can say that </em><em>the relationship</em><em> of these three concepts is that they all talk about the slope of a curve.</em>

sdas [7]3 years ago
3 0
<span><span>
It introduces the relationship between two variables and is called correlation. Proportionality or variation is state of relationship or correlation between two variables It has two types: </span>direct variation or proportion which states both variables are positively correlation. It is when both the variables increase or decrease together. On the contrary, indirect variation or proportion indicates negative relationship or correlation. Elaborately, the opposite of what happens to direct variation. One increases with the other variables, you got it, decreases. This correlations are important to consider because you can determine and identify how two variables relates with one another. Notice x = y (direct), y=1/x (indirect)</span>
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write an equation in slope intercept form for the line described. perpendicular to y = -1/2x + 2/3, passes through (2,3)
Alex17521 [72]

Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
  • Use the condition of perpendicular lines and find the slope of first equation.
  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

y =  \frac{ - 1}{2} x +  \frac{2}{3}

2nd equation..

Now, From equation (ii)

We have;

Comparing equation (ii) with y = mx+c.

We get;

Slope = -1/2.

For perpendicular lines,

m1 \times m2 =  - 1

m1 \times  \frac{ - 1}{2}  =  - 1

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
Please help me solve this problem
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How to reflect a point on a unit circle across axis?
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3 years ago
Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}
sashaice [31]

Hey there!

Assuming you meant

5r^2 - 12 = 68

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to add by 12 on each of your sides

5r^2 -12 +12 \\ \\ 68 + 12

5r^2 = 5r^2 \\ \\ 68 + 12 = 80

We get: 5r^2 =80

Now, we have divide by 5 on each of your sides

\frac{5r^2}{5} = \frac{80}{5}

\frac{80}{5}  = 16

We get: r^2 = 16

r = ± \sqrt{16}

Therefore , your answer is:r = ±4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0
3 years ago
Identify the two tables which represent quadratic relationships
madam [21]

Answer:

Option (4) and Option (5)

Step-by-step explanation:

By calculating the second difference, if the second difference in a table is equal, table will represent the quadratic relationship.

In the given option, we analyze that table given in Option (4) will represent the quadratic relationship.

x             y             Ist difference (y_2-y_1)         IInd difference

0            4                      -                                             -

1            -4             -4 - (4) = -8                                     -    

2           -4             -4 - (-4) = 0                              0 - (-8) = 8

3            4              4 - (-4) = 8                                  8 - 0 = 8

Second difference of the terms in y are the same as 8.

Therefore, table of Option (4) represents the quadratic relationship.

Similarly, in Option (5) we will calculate the second difference of y terms.

x            y            Ist difference     IInd difference

0          -4                    -                            -

1           -8             -8 - (-4) = -4                 -

2          -10           -10 - (-8) = -2        -2 - (-4) = 2      

3          -10           -10 - (-10) = 0        0 - (-2) = 2

Here the second difference is same as 2.

Therefore, table of Option (5) will represent the quadratic relationship.

6 0
3 years ago
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