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2 years ago

|x - 12| = 4 please provide an explanation

Mathematics

1 answer:

geniusboy [140]2 years ago

4 0

Answer: x = 16, x = 8

Step-by-step explanation:

|a| > 0, there are two solutions

|a| = 0, there is one solution

|a| < 0, there are no solutions

So, in this problem, we have two solutions.

In absolute value, the expression inside can be equal to itself OR its opposite.

Ex: |y| = y, |y| = -y

So, we can write two equations:

x - 12 = 4, x = 16

-x+12 = 4, x = 8

Check: |16 - 12| = |4| = 4

Check: |8 - 12| = |-4| = 4

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The witness did not state WHETHER the victim was on the east or west side of the street.

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3 years ago

45 POINTS PLEASE HELP!

andrew-mc [135]

Hello,

Question:

Jack popped some popcorn, but 3 of the 150 kernels did not pop.

Determine which popcorn snacks below has the same ratio of unpopped to total kernels as Jack's popcorn.

We Know:

3 out of 150 did not pop

Solution:

3/150 = 3 to 150

Find ratios similar to this one,

4/200

2/100

1/50

So now we know for every kernel that dosent pop there are 50 that did.

Answers:

4 unpopped out of 200 kernels

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8 0

4 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

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3 years ago

0.05% as a fraction in simplest form

fiasKO [112]

0.05=5/100
5/100=1/20

3 0

3 years ago

20 is what present of 30?

tia_tia [17]

66.6667

20=x/100•30
Solve this equation and you will get your answer (66.6667)

6 0

3 years ago