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tankabanditka [31]

2 years ago

7

Please help me this is important

1 answer:

Dmitrij [34]2 years ago

4 0

Answer:

C. II, III, and IV only

Step-by-step explanation:

Lol I haven't done one of these in a while, so thanks for the practice!

It's important to note that a dilation does NOT change the angles of the shape whatsoever. By this, you know that II and III are automatically correct, which rules out A and B. After that, you can look at I, which is the only difference between C and D. Since the dilation factor is 2/3, the parallelogram you see is smaller than the original. Since in I, the original would be larger than the denominator, the correct answer would be at least greater than one (to be precise, it'd be 3/2). To make everything easier, you can find the value by assigning the original side a value of 1, which would make the prime value 2/3. 1/(2/3) is going to be 3/2.

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Expand and simplify (x+6)(x−11)

KatRina [158]

Answer:

x^2 - 5x - 66

Step-by-step explanation:

1. Distrubute the x to the x and -11 so you will get x^2 - 11x

2. Distrubute the 6 to x and -11 and you get 6x - 66

3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66

7 0

1 year ago

It is known that 25% of inhabitants of a community favour a political party A.

Keith_Richards [23]

Answer:

i) $P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669$

ii) $P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317$

$P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211$

$P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669$

And replacing we got:

$P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883$

iii) $P(X$

Step-by-step explanation:

Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:

$X \sim Binom(n=20, p=0.25)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part i

We want this probability:

$P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669$

Part ii

We want this probability:

$P(X\geq 3)$

And we can use the complement rule and we have:

$P(X\geq 3) = 1-P(X$

And if we find the individual probabilites we got:

$P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317$

$P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211$

$P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669$

And replacing we got:

$P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883$

Part iii

We want this probability:

$P(X$

And replacing we got:

$P(X$

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Step-by-step explanation:

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Step-by-step explanation:

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