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Arte-miy333 [17]
4 years ago
10

A father is four times as old as his daughter. In 18 years he will be two times as old as she. How old is the daughter now?

Mathematics
1 answer:
irina [24]4 years ago
8 0
Let's say x to the daughter's age, since the father's age is four times the daughter's age, his age will be 4x. 18 years later, the daughter's age will be x+18 and the father's will be 4x+18. And we know that 18 years later the father's age will be twice the daughter' so , 4x+18 = 2(x+18) and 4x+18=2x+36 then, 4x-2x=36-18,
2x=18 then divide both sides by 2, x = 9. The daughter's age was x, so she is 9 years old.
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