The sodium-potassium pump of cell function is to take 2 potassium atoms into cells and dump the 3 sodium outside cells. The pump is also needed ATP as energy to make it work. That is why the pump sometimes referred as Na3/K2 ATPase pump.
The pump cannot do these things separately. That means if there are much potassium outside cells but there is no sodium, the pump will catch and keep the potassium then wait until they find sodium inside cells. If there is no sodium inside cells, the pump will not work even if there is much potassium outside.
Answer:
A. [isocitrate]/[citrate] = 0.724
B. [citrate] = 24.1 mM
Explanation:
Using the equation, ∆G'° = -RTlnK'eq
Where, ∆G'° = 0.8 KJ/mol = 800 J/mol; R is molar gas constant = 8.315 J/mol; T is standard temperature = 298 K; Keq is equilibrium constant = [isocitrate]/[citrate]
Making Keq subject of formula in the above equation;
Keq = e^(-∆G'°/RT)
= e^ {-800/(8.315*298)}
= e^(-0.323)
Keq = 0.724
Therefore, [isocitrate]/[citrate] = 0.
724
B. Keq = [isocitrate]/[citrate]
Where Keq = 0.724, [isocitrate] = 0.03mM.
[citrate] = Keq/[isocitrate]
= 0.724/0.03
[citrate] = 24.1 mM
CO2. An ionic compound is a metal and a nonmetal.
The correct answer is A. Diamond is an example of elemental carbon. It is an allotrope of carbon where the atoms are arranged in a face-centered cubic crystal structure. It is less stable than the other allotrope of carbon which is graphite.
If the concentration of enzyme increases, then reaction should speed up (answer C).
enzyme speeds up a chemical reaction by lowering activation energy to provide an alternative pathway of reaction mechanism. assuming that enzyme which usually is the limiting factor, the increase of enzyme concentration should lead to more product formation i.e. maltose from the breakdown of starch.
the enzyme discussed here should be amylase.
higher temperature beyond optimum value enzyme found in our human body will usually least to denaturation of active site of enzyme. hence lead to loss of enzyme activity permanently.