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3 years ago

When a liquid is heated, the temperature stops rising at the liquid’s ____________________.

Chemistry

2 answers:

Nata [24]3 years ago

8 0

<u>Answer: </u>

When liquid is heated, the temperature stops rising at the liquid's Boiling Point .

<u>Explanation: </u>

Boiling point is defined as the temperature at which pressure applied by the surroundings upon a liquid is normalised by the pressure applied by the vapour of the liquid. Under this condition, heating of the liquid transforms the liquid into its vapour without raise in the temperature .

The pressure of the vapour increases when temperature is increased. The liquid starts forming bubbles of vapour and move towards the surface at its boiling point. Based on the Pressure applied liquid have different boiling points. Higher the altitude, lower the boilng point temperature.

Agata [3.3K]3 years ago

5 0

Hi there,

the answer to the blank is: boiling point

When a liquid is heated, the temperature stops rising at the liquid's boiling point.

Hope this is correct :)

Have a great day

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A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

The microscopes used today are just like the ones used by Leeuwenhoek and Hooke. True or false

Dmitry [639]

Answer:

False

Explanation:

While we do know that A. Leeuwenhoek used a simple microscope that consisted of only 1 lens, Hooke used a compound microscope. Although, after trying a compound microscope, Hooke found out that it strained his eyes and continued to use a simple microscope for his <em>Micrographia</em>.

Thus, we can say that the (compound) microscopes used today are different than the (simple) microscope used by Hooke and Leeuwenhoek.

6 0

2 years ago

Conduction is when heat is transferred through

Nastasia [14]

The correct answer is a the sun

3 0

3 years ago

Read 2 more answers

An aqueous solution of blue copper(II) ions can react with chloride ions to form a yellow copper compound. The ionic equation fo

klio [65]

Since the forward reaction is endothermic (heat is consumed in the reaction) that means that the enthalpy change for the forward reaction is a positive value.
Therefore, i would say that the reverse or backward reaction is exothermic (heat is released in the reaction to the sorroundings) and that the enthalpy change is a negative value.

5 0

3 years ago

Given 6.23 mol Al find the atoms of Al

swat32

Answer:

The answer is

<h3>3.75 × 10²⁴ atoms of Al</h3>

Explanation:

To find the number of atoms of Al given it's number of moles we use the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 6.23 mol

We have

N = 6.23 × 6.02 × 10²³

We have the final answer as

<h3>3.75 × 10²⁴ atoms of Al</h3>

Hope this helps you

3 0

3 years ago