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3 years ago

When a liquid is heated, the temperature stops rising at the liquid’s ____________________.

Chemistry

2 answers:

Nata [24]3 years ago

8 0

Answer:

When liquid is heated, the temperature stops rising at the liquid's Boiling Point .

Explanation:

Boiling point is defined as the temperature at which pressure applied by the surroundings upon a liquid is normalised by the pressure applied by the vapour of the liquid. Under this condition, heating of the liquid transforms the liquid into its vapour without raise in the temperature .

The pressure of the vapour increases when temperature is increased. The liquid starts forming bubbles of vapour and move towards the surface at its boiling point. Based on the Pressure applied liquid have different boiling points. Higher the altitude, lower the boilng point temperature.

Agata [3.3K]3 years ago

5 0

Hi there,

the answer to the blank is: boiling point

When a liquid is heated, the temperature stops rising at the liquid's boiling point.

Hope this is correct :)

Have a great day

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two objects each have a mass of 5.0 g. one had a density of 2.7 g. and the other has a density of 8.4 g. which object has a larg

gulaghasi [49]

Answer:

The body with 2.7 $\frac{g}{(cm^3)}$ has a larger volume

Explanation:

There is a missespelling in the question. The units of density cannot be g, they usually are $\frac{g}{(cm^3)}$

In order to answer this question, we need to use the formula of the density of a body:

$Density = \frac{Mass}{Volume} = \frac{M}{V}$

For body A:

Mass (M) = 5.0 g

Density (D) = 2.7 $\frac{g}{(cm^3)}$

2.7 $\frac{g}{(cm^3)}$ = 5g * 1/V

V1 = 5g / (2.7 $\frac{g}{(cm^3)}$ )

V1 = 1.85 $1.85 cm^3$

For Body B:

Mass (M) = 5.0 g

Density (D) = 8.4 $\frac{g}{(cm^3)}$

8.4 $\frac{g}{(cm^3)}$ = 5g * 1/V

V2 = 5g / (8.4 $\frac{g}{(cm^3)}$ )

V2 = 0.59 $1.85 cm^3$

So V1 is bigger than V2

5 0

3 years ago

Help me plz I don’t know what it’s mean

Pavlova-9 [17]

Answer:

1 has the highest density because it has the most amount of circles in the least amount of space- it is the most densely filled with circles; it is the most dense.

4 0

3 years ago

Read 2 more answers

What, if any, is the relationship between atomic radius, ionization energy and electronegativity?

TEA [102]

All 3 increase going right to left and top to bottom on the periodic table

5 0

3 years ago

a 15.0 L tank of gas is contained at a high pressure of 8.20*10^4. The tank is opened and the gas expands into an empty chamber

Nostrana [21]

Answer:

$P_2=20.5$

Explanation:

Assuming that temperature is constant

According to Boyle's Law, at constant temperature pressure is inversly proportional to the volume and mathematically it can be expressed as:

$P_1V_1 = P_2V_2$ ..........1

$P_1=8.2 \times 10^4$

$P_2=?$

$V_1=15L$

$V_2=6.00 \times 10^4L$

from the first equation after putting all the value

we get,

$P_2=20.5$

8 0

3 years ago

Ammonia can be produced in the laboratory by heating ammonium chloride

AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl + Ca(OH)₂ → CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

NH₄Cl : NH₃

2 : 2

0.17 : 0.17

Ca(OH)₂ : NH₃

1 : 2

0.10 : 2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0

3 years ago