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tankabanditka [31]
3 years ago
9

When a liquid is heated, the temperature stops rising at the liquid’s ____________________.

Chemistry
2 answers:
Nata [24]3 years ago
8 0

<u>Answer: </u>

When liquid is heated, the temperature stops rising at the liquid's Boiling Point .

<u>Explanation: </u>

Boiling point is defined as the temperature at which  pressure applied by the surroundings upon a liquid is normalised by the pressure applied by the vapour of the liquid. Under this condition, heating of the liquid transforms the liquid into its vapour without raise in the temperature .

The pressure of the vapour increases when temperature is increased.  The liquid starts forming bubbles of vapour and  move towards the surface at its boiling point.  Based on the Pressure  applied  liquid have different boiling points.  Higher the altitude, lower the boilng point temperature.

Agata [3.3K]3 years ago
5 0

Hi there,

the answer to the blank is: boiling point

When a liquid is heated, the temperature stops rising at the liquid's boiling point.

Hope this is correct :)

Have a great day

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A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
3 years ago
*PLEASE HELP ASAP*
sveticcg [70]
Trueeeee !! :D it’s true because they change properties
7 0
3 years ago
Is 2OH−+Ca2+−&gt;2Ca(OH)2 balanced
wariber [46]

Answer:

No.

Explanation:

No.  There is 1 atom of Ca on the left and 2 Ca's on the right  and 2 OH's on the left and 4 on the right.

The balanced equation is:

4OH-  +  2Ca2+ ---->  2Ca(OH)2.

3 0
3 years ago
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REY [17]

Answer:

0.682L or 682mL

Use Charles Law of V1/T1 = V2/T2

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T2= 333K

Explanation:

?

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Answer: Water because if we say aqueous it means it resembles water or related to water.

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