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3 years ago

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a solution of hydrochloric acid contains 1.5 moles of the solute in 2.0 liters of solution. calculate the molarity of this solut

ion

1 answer:

Orlov [11]3 years ago

3 0

Answer:

0.75 M

Explanation:

Molarity = moles of solute / liters of solution

so;

Molarity = $\frac{1.5 Moles}{2.0 Liters}$

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If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n

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Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

$2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}$

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

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A red blood cell placed in saline solution will shrink.<br> True or false? Explain please?

Scorpion4ik [409]

Yes a red blood cell placed in a sline solution shrinks because of the process of osmosis.

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For the reaction: N2O5(g) \longrightarrow&longrightarrow; 2NO2(g) + 1/2O2(g)

ivanzaharov [21]

The given equation from the problem above is already balance,
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Hey there! Let's get that problem solved!

First: Let's define, "solution."

Solution: <span>a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).

Next: Ask yourself, "can a solution be taken apart?"

In some cases, yes. It can.

The solution of salt water for example, can be physically separated by evaporation. (place salt-water in a pot on a heated stove, place the cover to the pot on the opening, wait a few minutes, remove the top, and you can (and taste) the water without the salt!) </span><span />

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3 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

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3 years ago