For 5, we can make 1/csc x = sinx, but we're then left with sin^2+cos^2x(sinx)=sin(sin+cos^2x), which doesn't give us anything. False.
For 7, we know that cosx= tanx/sinx and cotx=1/tanx, so we cross out the tan x's and get 1/sinx, which is not sinx. False
15 - (1-cos^2u)/cos^2u=tan^2u, turn 1-cos^2u=sin^2u and square root both sides to get sin/cos=tan
17 - tanx = sinx/cosx, so multiply that with sinx on the right to get sin^2x/cosx, and multiply both sides by cosx to get cos^2x-1=sin^2x (assuming that (cos^2x-1)/cosx is what was meant on the right)
23 - don't know how to prove that true, sorry
31 - (cos^4x-sin^4x)=(cosx+sinx)(cosx-sinx)(cos^2x+sin^2x)=(cosx+sinx)(cosx-sinx)=cos^2x-sin^2x
Answer:
C
Step-by-step explanation:
18's factors are 2 * 3 * 3
The two 3s can reduce the result further. sqrt (2 * 3 * 3)
square root 18 = 3*sqrt(2)
There are two sides with this length. Their total is 3sqrt(2) + 3sqrt(2) = 6√2
The perimeter is the sum of all three sides = 6 + 6√2
Answer:
Yes the car was speeding
Step-by-step explanation:
s = √(30fd) where
- s is the speed of the car in mph
- f is the coefficient of friction for the road
- d is the length in feet of the skid marks
Substitute d = 41.5 and f = 0.8 into the equation:
s = √(30 x 0.8 x 41.5)
⇒ s = √(996)
⇒ s = 31.55946768...
Therefore, for these data, the speed of the car was 31.56 mph (to the nearest hundredth)
The speed limit was 30 mph, therefore the car was speeding as 31.56 > 30
16) 9y+2r If she bought 1 dog toy and 2 treats: 9(1)+2(2)= 13
17) 5n-3n= 2n
17-2+7= 22 Combine like terms
2n+22 Write out expression
2(8)+22= 38 Plug in 8.
Answer: 2n+22; 38
18) 5h^3 h represents the # of weeks; Find # of tickets sold in 3 weeks:h=3
5(3)^3 plug in 3
5(27) PEMDAS; Exponents first; 3*3*3= 27
Answer: 135
19) It is true
If d=2, 5(2)*5(2)*5(2)= (5*2)^3
10*10*10=(10)^3
1,000=1,000
Given :
Two equation 
and 
.
To Find :
The point of intersection of these lines .
Solution :
We will use elimination method :
From equation 1 :
Putting value of 
in equation 2 we get :
Putting value of 
in equation 1 we get :
Therefore , point of interaction is 
.
Hence , this is the required solution .
