The mass of a particle is 2.2x10⁻¹⁵ kg
Consider smoke particles as an ideal gas
The translational RMS speed of the smoke particles is 2.45x10⁻³ m/s.
<em>v= √3kT/m</em>
<em>where k= 1.38x10⁻²³J/K, T is 288K, and m is the mass of the smoke particle</em>
<em>2.45x10⁻³ = √3x1.38x10⁻²³x288/m</em>
<em>m= 2.2x10⁻¹⁵ kg</em>
Therefore, the mass of a particle is 2.2x10⁻¹⁵ kg.
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first is gamma Ray's, last is d
Given:
rate of effusion of Helium = 6 hours
Data needed:
Molar mass of hydrogen gas = 2 g/mol
Molar mass of helium gas = 4 g/mol
Assume:
Constant conditions such as temperature and pressure.
Required:
rate of effusion of Hydrogen gas
Solution:
To solve the problem, we can use the formula:
rate of effusion of A/ rate of effusion of B = (molar mass of B/molar mass of A)^1/2
substituting values,
rate of effusion of hydrogen gas/ 6 hours = (4 g/mol/2 g/mol)^1/2
rate of effusion of hydrogen gas = 8.5 hours
Answer:
If the ball were thrown from the ground or even landed at an equal height (40m here), then yes, the time would be a 1:1 ratio of flight to fall.
But the ball is thrown from a height of 40m, so it will take longer to hit the ground.
For example, while it may take, say, 3 seconds to go up to its max height and 3 seconds to reach it's original height again, it may take 4 more seconds to finally reach the ground.
