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3 years ago

The student moves his leg 34 cm sideways as shown.

Physics

2 answers:

Nana76 [90]3 years ago

8 0

(i) • there is force applied to an objects

• the object moves

• the object moves in the same direction as the direction of the force

(ii) workdone = force x distance

= 23 x 34

= 782Joules

jenyasd209 [6]3 years ago

5 0

Answer:

Question A1:

Workdone=force x distance

Question A11:

7.82 joules

Explanation:

question A1:

The relationship between work done, force and distance is that workdone can be calculated by multiplying force and distance

Question A11:

Force=23N

Distance=34cm=0.34m

Work done=force x distance

Work done=23 x 0.34

Workdone=7.82J

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Which of newtons laws accounts for the following statement " Negative acceleration is proportional to applied braking force "

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4 years ago

Calculate the pressure exerted by 11.1 moles of neon gas in a volume of 5.45 L at 25°C using (a) the ideal gas equation and (b)

Ilia_Sergeevich [38]

Answer:

49.82414 atm

50.74675 atm

Explanation:

P = Pressure

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a = 0.211 atm L²/mol²

b = 0.0171 atm L²/mol²

From ideal gas law we have

$PV=nRT\\\Rightarrow P=\dfrac{nRT}{V}\\\Rightarrow P=\dfrac{11.1\times 0.08205(273.15+25)}{5.45}\\\Rightarrow P=49.82414\ atm$

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From Van der Waals equation we have

$\left(P+\frac{an^2}{V^2}\right)\left(v-nb\right)=nRT\\\Rightarrow P=\dfrac{nRT}{V-nb}-\dfrac{an^2}{V^2}\\\Rightarrow P=\dfrac{11.1\times 0.08205\times (273.15+25)}{5.45-(11.1\times 0.0171)}-\dfrac{0.211\times 11.1^2}{5.45^2}\\\Rightarrow P=50.74675\ atm$

The pressure is 50.74675 atm

3 0

3 years ago

The red car drive on a motor way in 800 m/s.The

Black_prince [1.1K]

800/20=40
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7 0

3 years ago

If an object is accelerating, the forces acting on it must be ___.

I am Lyosha [343]

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6 0

3 years ago

A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force

sasho [114]

Answer:

C) 50 m/s

Explanation:

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List out known variables:

v₀ = 0 m/s
a = 5 m/s²
v = ?
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Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

v² = (0)² + 2(5)(250)
v² = 2500
v = 50 m/s

The final velocity of the box is C) 50 m/s.

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3 years ago