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statuscvo [17]
2 years ago
10

Help plz I’ll mark brainliest

Physics
2 answers:
Scorpion4ik [409]2 years ago
6 0

Answer:

concave

Explanation:

the middle of the concave lens is narrow and the edges are flattened.

marin [14]2 years ago
3 0
I think it’s concave
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A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is r
aivan3 [116]

Answer:

Explanation:

Given that,

Initial angular velocity is 0

ωo=0rad/s

It has angular velocity of 11rev/sec

ωi=11rev/sec

1rev=2πrad

Then, wi=11rev/sec ×2πrad

wi=22πrad/sec

And after 30 revolution

θ=30revolution

θ=30×2πrad

θ=60πrad

Final angular velocity is

ωf=18rev/sec

ωf=18×2πrad/sec

ωf=36πrad/sec

a. Angular acceleration(α)

Then, angular acceleration is given as

wf²=wi²+2αθ

(36π)²=(22π)²+2α×60π

(36π)²-(22π)²=120πα

Then, 120πα = 8014.119

α=8014.119/120π

α=21.26 rad/s²

Let. convert to revolution /sec²

α=21.26/2π

α=3.38rev/sec

b. Time Taken to complete 30revolution

θ=60πrad

∆θ= ½(wf+wi)•t

60π=½(36π+22π)t

60π×2=58πt

Then, t=120π/58π

t=2.07seconds

c. Time to reach 11rev/sec

wf=wo+αt

22π=0+21.26t

22π=21.26t

Then, t=22π/21.26

t=3.251seconds

d. Number of revolution to get to 11rev/s

∆θ= ½(wf+wo)•t

∆θ= ½(0+11)•3.251

∆θ= ½(11)•3.251

∆θ= 17.88rev.

5 0
3 years ago
Read 2 more answers
Acceleration = change of velocity divided by time interval = Δv/Δt.
MariettaO [177]

Answer:

a=2.378 m/s^2

Explanation:

a=Δv/Δt------eq(1)

Δv=Vf-Vi=120 km/h-0 km/h=120 km/h

or Δv=33.3 m/sec

or time=t=14s

putting values in eq(1)

a=33.3/14

a=2.378 m/s^2

6 0
3 years ago
What is the net work on the block?
Strike441 [17]

Answer:

A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size

8 0
3 years ago
"What kind of electromagnetic radiation can be detected by a human body? I) visible light II) infrared light III) ultra-violet l
Vinvika [58]

Answer:

7. I and III only.

Explanation:

Only portions of the electromagnetic spectrum is visible to the human eye. Electromagnetic radiation in this range of wavelengths is called visible light which have wavelengths from about 390 to 750 nm that is; ultraviolet light and visible light.

4 0
3 years ago
What would be the weight of the moon if it were resting on the surface of the earth
kari74 [83]
We need to be careful here.
The calculation of the gravitational force between two objects
refers to the distance between their centers. 
The minimum possible distance between the Earth's and moon's
centers is the sum of their radii (radiuses).

Earth's radius . . . . .  6,360 km  =  6.36 x 10⁶ meters
Moon's radius . . . . .  1,738 km  =  1.738 x 10⁶ meters
Sum of their radii  =                      8.098 x 10⁶ meters

Also:
Earth's mass . . . . .  5.972 x 10²⁴ kg
Moon's mass . . . . .  7.348 x 10²²  kg
<span>
and now we're ready to go !

       Gravitational force = 

                   G  M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(</span><span>5.972 x 10²⁴ kg)(7.348 x 10²²  kg)/</span>(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³)      Newtons

=    (I get ...)        4.463 x 10²³ Newtons

That's almost exactly   10²³ pounds 

                           =  50,153,000,000,000,000,000 tons.     

Those are big numbers. 
All I can say is:  I wouldn't exactly call that "resting" on the surface".
7 0
3 years ago
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