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skelet666 [1.2K]
3 years ago
12

A student pushes a chair into a desk. If the student's push is the action force, then what is the reaction force in this example

of Newton's third law?
A the force from the chair on the student
B the force that the chair exerts on the desk after it is pushed in
C the force of friction acting on the chair
D the force of gravity acting on the chair
Physics
2 answers:
Brrunno [24]3 years ago
7 0

Answer: C

Explanation:

Lana71 [14]3 years ago
7 0
C
The force of friction. Is acting on the chair
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Carbon dioxide can be represented by the chemical formula
Vitek1552 [10]

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Your answer is B co2

Explanation:

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Does the Earth stay in one place throughout the year? If it doesn't, describe its motion and where it's located in the solar syt
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6 0
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The equation for the speed of an electromagnetic wave is
igomit [66]

Answer:

c = 1 / √(ε₀*μ₀)

Explanation:

The speed of the electromagnetic wave in free space is given in terms of the permeability and the permittivity of free space by

c = 1 / √(ε₀*μ₀)

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4 0
3 years ago
2. A 55 kg woman has a momentum of 200 kg m/s. What is her velocity?
NeTakaya

Answer:

\boxed {\tt 3.63636364 \ m/s}

Explanation:

Velocity can be found using the following formula:

v=\frac{p}{m}

where p is the momentum and m is the mass.

The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

p= 200 \ kgm/s\\m=55 \ kg

Substitute the values into the formula.

v=\frac{200 \ kg m/s}{55 \ kg}

Divide. Note that the kilograms, or kg, will cancel each other out.

v=\frac{200 \ m/s}{55}

v= 3.63636364 \ m/s

The woman's velocity is 3.63636364 meters per second.

6 0
3 years ago
A $100 cart is moving down an inclined plane at 1.30 m/s. The cart collides with a stationary object and rebounds with a speed o
Rasek [7]

Answer:

0.65  kg*m/s and 0.165 kg*m/s

Explanation:

Step one:

given data

mass m= 0.5kg

initial velolcity u=1.3m/s

final velocity v= 0.97m/s

Required

The change in momentum

Step two:

We know that the expression for impulse is given as

Ft= mv

Ft= 0.5*1.3

Ft= 0.65  kg*m/s

The expression for the change in momentum is given as

P= mΔv

substitute

Pt= 0.5*(1.3-0.97)

Pt= 0.5*0.33

Pt=0.165 kg*m/s

7 0
3 years ago
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