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Salsk061 [2.6K]

2 years ago

11

What type of heat does not require matter?

2 answers:

koban [17]2 years ago

8 0

Radiation is the only method of heat transfer that does not require matter.<u> </u>

<u>Facts</u><u> </u><u>about</u><u> </u><u>Radiation</u> :

The energy from the sun is received in the form of radiation.
It travels in the form of waves.
It can be absorbed by substances in its path.
Heat Radiation travels through air.
Black surfaces are the emitters of heat radiation.
Shiny surfaces are the reflectors of heat radiation.
Heat transfer by Radiation doesn't require any medium.

Lana71 [14]2 years ago

4 0

It would be Thermal Radiation

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c) $PE_{f} =0.5\ PE_{i}$

Explanation:

A parallel plate capacitor with $C_{o}$ that is connected to a voltage source $V_{o}$ holds a charge of $Q_{o} =C_{o} V_{o}$ . Then we disconnect the voltage source and keep the charge $Q_{o}$ constant . If we insert a dielectric of $\kappa=2$ between the plates while we keep the charge constant, we found that the potential decreases as:

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The stored energy without the dielectric is

$PE_{i}=\frac{1}{2}\frac{Q_{o}^{2}}{C_{o}}=\frac{1}{2}C_{o}V_{o}^{2}$

The stored energy after the dielectric is inserted is:

$PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}$

If we replace in the above equation the values of V and C we get that

$PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})$

$PE_{f} =\frac{PE_{i}}{\kappa}$

Finally

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