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CaHeK987 [17]
4 years ago
9

A man pushes on a trunk with a force of 250 newtons. The trunk does not move. How much positive work is done on the trunk?

Physics
1 answer:
Digiron [165]4 years ago
3 0

Answer:

F is 250 N

d is 0 m

F x d

=250 x 0

=0

The answer is 0.0 J.

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During an ultrasound, sound waves are sent by a transducer through muscle tissue at a speed of 1300 m/s. Some of the sound waves
alina1380 [7]

2.3 \times 10^{-5} \text { seconds } is the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted

Option C

<u>Explanation:</u>

Given data:

speed, v = 1300 m/s

distance, d = 3.0 cm = 3.00 \times 10^{-2} \mathrm{m}

We need to calculate the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted.

As we know, the velocity is the ratio of distance and the time travelled by an object. The equation form is given by,

              \text {velocity, } v=\frac{\text {distance }(d)}{\text {time}(t)}

By applying the given values to the above equation, we get

              1300=\frac{3.00 \times 10^{-2}}{t}

              t=\frac{3.00 \times 10^{-2}}{1300}=0.002307 \times 10^{-2}=2.3 \times 10^{-5} \text { seconds }

7 0
4 years ago
What is the Celsius eguivalent of 212°F?<br> 32°C<br> 0°C<br> 100°C<br> 212°C
sweet-ann [11.9K]

Answer:

100°C

Explanation:

4 0
4 years ago
Read 2 more answers
Two football players run towards each other along a straight path in Penrith Park in the clash between the Melbourne storms and
Agata [3.3K]

Answer:

a) v = 0.4799 m / s,  b)  K₀ = 1600.92 J,    K_f = 5.46 J

Explanation:

a) How the two players collide this is a momentum conservation exercise. Let's define a system formed by the two players, so that the forces during the collision are internal and also the system is isolated, so the moment is conserved.

Initial instant. Before the crash

        p₀ = m v₁ + M v₂

where m = 95 kg and his velocity is v₁ = -3.75 m / s, the other player's data is M = 111 kg with velocity v₂ = 4.10 m / s, we have selected the direction of this player as positive

Final moment. After the crash

       p_f = (m + M) v

as the system is isolated, the moment is preserved

       p₀ = p_f

       m v₁ + M v₂ = (m + M) v

       v =\frac{m v_1 + M v_2}{m+M}

let's calculate

        v = \frac{ -95 \ 3.75 \ + 111 \ 4.10}{95+111}

        v = 0.4799 m / s

b) let's find the initial kinetic energy of the system

         K₀ = ½ m v1 ^ 2 + ½ M v2 ^ 2

         K₀ = ½ 95 3.75 ^ 2 + ½ 111 4.10 ^ 2

         K₀ = 1600.92 J

the final kinetic energy

         K_f = ½ (m + M) v ^ 2

         k_f = ½ (95 + 111) 0.4799 ^ 2

         K_f = 5.46 J

3 0
3 years ago
The purpose of a motor is to:
WINSTONCH [101]

Answer:

a motor is used to covert electrical energy to mechanical energy

7 0
3 years ago
What is the electrical force between q2 and q3? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 1.0 × 1011 n
max2010maxim [7]

The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

<h3>What is the magnitude of electrical forces between two charges?</h3>

The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.

The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

F = \frac{K \times q_2 \times q_3}{d^{2}}

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

Learn more about electrical force at: brainly.com/question/17692887

#SPJ4

6 0
2 years ago
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