Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Answer:
add plants and trees
Explanation:
they help hold the soil in place because of their roots
When the structure and function of an organism adjusts to its environment it is adapting.
Answer:
The answer to the given question out of the four options provided is given by:
Option a. Hydrolysis products are more resonance stabilized.
Explanation:
The answer selection to the above question can be justified as Phosphoanhydride on hydrolysis releases free high energy as the bonds formed by phosphoanhydride are the bonds with high energy.
Therefore, the product of hydrolysis after releasing this energy is more resonance stabilized.
Answer:
Ribosomes are the site where <em>proteins </em>are produced. Amino acids are coded for by triplet bases in RNA called <em>codons</em>. Hope this helps
