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Finger [1]
3 years ago
11

Translate the phrase into an algebraic expression: the quotient of a number and three.

Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

x ÷ 3 or \frac{x}{3}

Step-by-step explanation:

Hi there! I'm glad I was able to help you out!

The word 'quotient' implies that we are dividing.

Let's call the unidentified number x, to keep things simple.

The quotient of x and 3 would look like this:

x ÷ 3

Or, it could look like this:

\frac{x}{3}

I hope this helped you! Comment below if you have any further questions! :)

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How do you do -19+C/3=8 can someone teach how to solve this problem?
ki77a [65]
You're looking for c, so you want to isolate it or get it by itself. To get rid of the /3 you multiply since the opposite of division is multiplication and to get rid of it, you do the opposite (like -9 you would add 9 to get it to 0). Now you are left with -19+c = 24 (the 24 is 8*3 because what you do to one side you do to the other. Now you get c by itself so you add 19 to both sides which leaves you with C= 43. Sorry if this was confusing!
3 0
4 years ago
A function is expressed by the formula y = 2x + 7. Find the value of y if x is equal to 1; -20; 43.
rosijanka [135]

Answer:

when x = 1 then y = 9

when x = -20 then y = -33

when x = 43 then y = 93

Step-by-step explanation:

Just replace the given values of x ( which are 1 , -20 , 43 ) in the function

3 0
3 years ago
Can someone please help meeee?
Anarel [89]

Answer:

why

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!!!<br><br>ABCD is a parallelogram. Find x.
Diano4ka-milaya [45]

Answer:

here,x=123, is the answer.

4 0
4 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
arsen [322]

The shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

<h3>what will be the time in which the blocker will block the ball?</h3>

The given equation for ball height

=6+30t-16t^{2}

The equation for the blocker's height will be

=9+25t-16t^{2}

But, the shot is made before two-tenths of a second or 0.2 seconds therefore modified equation for ball height is

=6+30(t-0.2)-16(t-0.2)^{2}

Now for the shot to be blocked, the height of the shot-blocker must be greater than the height of the ball which is shot before 0.2 seconds :

9+25t-16t^{2} \geq 6+30(t-0.2)-16(t-0.2)^{2}

9+25t-16t^{2} \geq6+30t-6-16(t^{2} -0.4t+0.04)

9+25t-16t^{2} \geq30t-16t^{2} -6.4t+0.64

9+25t\geq36.4t-0.64

9.64\geq11.4t

t \leq \dfrac{9.64}{11.4}=0.846

Thus the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

To know more about the Equation of motions follow

brainly.com/question/25951773

5 0
2 years ago
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