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bija089 [108]
4 years ago
7

How to solve system of equation by graphing

Mathematics
1 answer:
frosja888 [35]4 years ago
4 0

Answer:

Step-by-step explanation: use the form y=mx+b

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Help plz <br> If SU = 110, find the value of x. Then find ST and TU.<br> 2x - 10<br> 5x + 50
sergij07 [2.7K]

Answer:

x=10

ST=10

TU=100

Step-by-step explanation:

2x-10 + 5x+50 = 110

2x+5x=110+10-50

7x=70

x=10

2(10)-10

20-10=10

5(10)+50

50+50=100

6 0
3 years ago
August hosted two dinner parties for his friends. Twenty guests attended the first party, and thirty-three guests attended the s
blondinia [14]

Answer:

50%

Step-by-step explanation:

4 0
3 years ago
To pass this year's math class, Miriam needs to earn at least an 82%. Write an inequality that shows the scores Miriam could get
sergey [27]

The inequality that shows the scores Miriam could get to pass her math class is 82\%\leq x \leq 100\%

<em><u>Solution:</u></em>

Given that To pass this year's math class, Miriam needs to earn at least an 82%

To find: Inequality that shows the scores Miriam could get to pass her math class

Let "x" be the Miriam's score in the math class

Given she should score at least 82 %

Therefore, we can frame a inequality as:

x\geq 82 \%

Here we used "greater than or equal to" , because she can score 82 % or more than 82 % also

The maximum score is 100 %

Hence we can frame a inequality as:

x\leq 100 \%

Here, we used "less than or equal to" , because she can score the maximum score of 100 % or less than 100 %

Combining both the inequalities we get,

82\%\leq x \leq 100\%

All real numbers greater than or equal to 82% and less than or equal to 100%

Thus the required inequality is found

6 0
3 years ago
Answerrrrrrrrrr??????
kumpel [21]

Answer: 1/b6

Step-by-step explanation:

3 0
3 years ago
An urn contains ten chips. An unknown number of chips are white' the others are red. We wish to test:
Olin [163]

Answer:

Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips  are white. Then,

a) Find α

α = P (reject H0 | H0 is true) = P (X ≥ 2|E)  

  = P (X = 2|E) + P (X = 3|E),    

We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution

  =  (5C2 * 5C1)/10C3  +  (5C3 * 5C0)/10C3

  =  0.5

So,  α = 0.5

b) Find β

i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)

β = P (accept H0 | E1) = P (X ≤ 1|E1)

  =  (6C0 * 4C3)/10C3  +  (6C1 * 4C2)/10C3

 = 1/3

 = 0.333

So, β = 0.333

i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)

β = P (accept H0 | E2) = P (X ≤ 1|E2)

  =  (7C0 * 3C3)/10C3  +  (7C1 * 3C2)/10C3

 = 11/60

 = 0.183

So, β = 0.183

5 0
4 years ago
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