Not entirely sure I this one
Graph 1:
Option B
Graph 2:
NOT Option A
NOT Option D
Maybe Option C
<u>RATE AS BRAINLIEST</u>
Answer:
Step-by-step explanation:
Bike 12.7 percent, decreases
Scooter 24 percent, increase
Tennis racket, 82.95
Skis 452.40
Answer:
the time percentage is 17%
Step-by-step explanation:
The computation of the time percenatge in the case when the detector lie and done with the mistake is as follows:
L denotes the event in which a person is lying.
NL denotes the event in which a person is not lying.
C denotes the event in which that lie detector works correctly
NC denotes the event in which lie detector is not working correctly
Now
P(C|L) =0.8
And,
P(NC|L) is
=1 - .8
= 0.2
P(C|NL) =0.9
P(NC|NL) is
= 1 -.9
=.1
P(L) = 0.7
P(NL) is
= 1 - .7
= .3
Now
P(NC) =P(NC|L) × P(L) + P(NC|NL) × P(NL)
=. 2 × .7 + .1 ×.3
=. 14+.03
= 0.17
Hence, the time percentage is 17%
<span>C)Use the Side-Splitting Theorem to find NI.</span>
Answer:
- There are two solutions:
- B = 58.7°, C = 82.3°, c = 6.6 cm
- B = 121.3°, C = 19.7°, c = 2.2 cm
Step-by-step explanation:
You are given a side and its opposite angle (a, A), so the Law of Sines can be used to solve the triangle. The side given is the shorter of the two given sides, so it is likely there are two solutions. (If the given side is the longer of the two, there will always be only one solution.)
The Law of Sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
Of course, the sum of angles in a triangle is 180°, so once you find angle B, you can use that fact to find angle C, thus side c.
The solution process finds angle B first:
B = arcsin(b/a·sin(A)) . . . . . . or the supplement of this value
then angle C:
C = 180° -A -B = 141° -B
finally, side c:
c = a·sin(C)/sin(A)
___
A triangle solver application for phone or tablet (or the one on your graphing calculator) can solve the triangle for you, or you can implement the above formulas in a spreadsheet (or even do them by hand). Of course, you need to pay attention to whether the functions involved give or take <em>radians</em> instead of <em>degrees</em>.