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faust18 [17]
3 years ago
13

Which gas is formed when h2co3 is produced in an aqueous solution

Chemistry
1 answer:
Rasek [7]3 years ago
4 0

Answer:

Carbon dioxide (CO₂)

Explanation:

Carbonic acid decomposes to release water and carbon dioxide:

H₂CO₃ →  H₂O + CO₂

In an aqueous solution, it has this two equilibriums where it release 2 protons. It is a weak acid:

H₂CO₃  + H₂O ⇄ HCO₃⁻  +  H₃O⁺         Ka₁

HCO₃⁻  +  H₂O ⇄  CO₃⁻²  +  H₃O⁺         Ka₂

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A solution is prepared by dissolving 4.66 g of KCl in enough distilled water to give 250 mL of solution. KCl is a strong electro
Leokris [45]

Answer:

Depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

Explanation:

On adding any non volatile solute to a solvent its boiling point increases and its freezing point decreases [these are two of the four colligative properties].

The depression in freezing point is related to molality of solution as:

ΔTf=iK_{f}Xmolality

where

ΔTf= depression in freezing point

Kf= cryoscopic constant of water = 1.853 K. kg/mol.

i = Van't Hoff factor = 2 ( for KCl)

molality = \frac{molesofsolute}{massofsolvent(Kg)}

moles of solute = mass / molarmass = 4.66 / 74.55 =0.0625

mass of solvent = mass of solution (almost)

considering the density of solution to be 1g/mL

mass of solvent = 250 grams = 0.250 Kg

molality = \frac{0.0625}{0.25}= 0.25

Putting values

depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

7 0
4 years ago
Read 2 more answers
A 75.0 mL 75.0 mL aliquot of a 1.70 M 1.70 M solution is diluted to a total volume of 278 mL. 278 mL. A 139 mL 139 mL portion of
Vlada [557]

Answer:

0.210 M

Explanation:

<em>A 75.0 mL aliquot of a 1.70 M solution is diluted to a total volume of 278 mL.</em>

In order to find out the resulting concentration (C₂) we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

1.70 M × 75.0 mL = C₂ × 278 mL

C₂ = 0.459 M

<em>A 139 mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive.</em>

Since the volumes are additive, the final volume V₂ is 139 mL + 165 mL = 304 mL. Next, we can use the dilution rule.

C₁ × V₁ = C₂ × V₂

0.459 M × 139 mL = C₂ × 304 mL

C₂ = 0.210 M

7 0
3 years ago
Read 2 more answers
Why must the electrical polarity of the tubes in a linear accelerator be reversed at very short time intervals?
aleksklad [387]

Polarity is a term used in electricity, magnetism, and electronic signaling. Suppose there is a constant voltage , also called an electric potential or electromotive force (EMF), between two objects or points. In such a situation, one of the objects or points (poles) has more electrons than the other.

<h3>What causes electrical polarity?</h3>

This happens when the hot and neutral wires get flipped around at an outlet, or upstream from an outlet. Reversed polarity creates a potential shock hazard, but it's usually an easy repair.

<h3>Why is electrical polarity important?</h3>

When working with electrical circuits, we often refer to the polarity between different points in the circuit. Understanding polarity is important for connecting the leads of polarity-dependent devices such as some meters and motors. Polarity is also important for determining the direction of current flow.

Learn more about polarity here:

<h3>brainly.com/question/20373607</h3><h3 /><h3>#SPJ4</h3>
8 0
2 years ago
How do you read and write sigfigs
m_a_m_a [10]

Rules for Numbers WITHOUT a Decimal Point

START counting for sig. figs. On the FIRST non-zero digit.

STOP counting for sig. figs. On the LAST non-zero digit.

Non-zero digits are ALWAYS significant.

Zeroes in between two non-zero digits are significant. All other zeroes are insignificant.

3 0
3 years ago
What is solubility limit?
uranmaximum [27]

Answer:

The maximum amount of a solute that can dissolve in a solvent at a specified temperature and pressure is its solubility.  Even for very soluble substances, however, there is usually a limit to how much solute can dissolve in a given quantity of solvent.

5 0
3 years ago
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