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Finger [1]
3 years ago
14

If you have 8.45 x 10^27 molecules of H2O, how many moles of water do you have?

Chemistry
1 answer:
il63 [147K]3 years ago
7 0

Answer:

<h3>The answer is 14036.54 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 8.45 x 10^27 molecules of H2O

We have

n =  \frac{8.45 \times  {10}^{27} }{6.02 \times  {10}^{23} }  \\  = 14036.544850...

We have the final answer as

<h3>14036.54 moles</h3>

Hope this helps you

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HELP! PLEASE! ASAP! Manganese(III) fluoride, MnF3, can be prepared by the following reaction:
Crank

Answer:

14.336 g MnF₂

Explanation:

number of moles = mass / molecular weight

number of moles of MnI₂ = 55 / 309 = 0.178 moles

number of moles of F₂ = 55 / 38 = 1.447 moles

From the reaction and the number of moles calculated we deduce that the fluorine F₂ is a limiting reactant.

So:

if        13 moles of F₂ reacts to produce 2 moles of MnF₃

then   1.447 moles of F₂ reacts to produce X moles of MnF₃

X = (1.447 × 2) / 13 = 0.223 moles of MnF₃ (100% yield)

For 57.2% yield we have:

number of moles of MnF₃ = (57.2 / 100) × 0.223 = 0.128 moles

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3 0
3 years ago
45 2.0
Mandarinka [93]

Answer:

The answer to your question is: Q = 3153600 Joules

Explanation:

Data

Q = ?

m = 48 kg

T1 = 21°C

T2 = 94°C

Cp = 900 J/g°C

Formula

Q = mCpΔT

Q = (48)(900)(94 - 21) = 3153600 Joules

3 0
3 years ago
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