-2a(3a to the power of 4)

the perimeter of a rectangular garden is 96m. The length of the garden is 8 more than the width. Find the length and width of th

SCORPION-xisa [38]

Answer:

width = 20

length = 28

Step-by-step explanation:

perimeter=96

width=x

length=x+8

(length*2) + (width*2) = perimeter

2(x+8) + 2(x) = 96

2x+16+2x=96

4x+16=96

4x=80

x=20

width = 20

length = 28

4 0

2 years ago

Write <img src="https://tex.z-dn.net/?f=%282a%29%5E3" id="TexFormula1" title="(2a)^3" alt="(2a)^3" align="absmiddle" class="late

Gre4nikov [31]

Hello ;
(2a)^3 =(2)^3 (a)^3 = 8(a)^3

7 0

3 years ago

Read 2 more answers

What is the range of the function in the given table?

Aloiza [94]

I think its b but im not sure

6 0

3 years ago

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Determine the total number of roots of each polynomial function f(x)=3x^6+2x^5+x4-2x^3

Alisiya [41]

Answer:

6 roots

Step-by-step explanation:

f(x)=3x^6+2x^5+x4-2x^3

The number of roots is determined by the degree of the polynomial. They may be real or complex.

Since this is a 6th degree polynomial, it will have 6 roots

f(x)=3x^6+2x^5+x4-2x^3

3 0

4 years ago

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago

-2a(3a to the power of 4)​

-2a(3a to the power of 4)