Hello!
Yes, it needs oxygen to metabolize sugars that, in the end, produce carbon dioxide (CO2).
Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m
Answer:
The answer is B
Explanation:
B is your answer hopes this helps you
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.
Hope it helps
2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement
2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition
2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement
2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition
