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chubhunter [2.5K]

3 years ago

15

Will mark brainliest!!!! 15 pts!!!!Please solve these equations

1 answer:

anastassius [24]3 years ago

5 0

2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement

2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement

2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition

2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement

2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition

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Two substances in a mixture differ in density and particle size. These properties can be used to

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I think the best answer from the choices listed above is option 1. <span>Two substances in a mixture differ in density and particle size. These properties can be used to separate the substances. These properties can be manipulated in order to have a better separation between the two substances.</span>

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Name two physical properties that could be used to distinguish between water and ethanol.

miskamm [114]

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11<br> Na<br> Sodium<br> 22.99<br> What does 22.99 stand for

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3 years ago

Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 97. g of octane is mi

zhannawk [14.2K]

Answer: 61 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles of octane}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{97g}{114g/mol}=0.85moles$

$\text{Number of moles of oxygen}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{150g}{32g/mol}=4.69moles$

The chemical equation for the combustion of octane in oxygen follows the equation:

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

By stoichiometry of the reaction;

25 moles of oxygen react with 2 moles of octane

4.69 moles of oxygen react with= $\frac{2}{25}\times 4.69=0.37$ moles of octane

Thus, oxygen is the limiting reagent as it limits the formation of product and octane is the excess reagent.

25 moles of oxygen produce 18 moles of water

4.69 moles of oxygen produce= $\frac{18}{25}\times 4.69=3.38$ moles of water.

Mass of water produced= $moles\times {\text{Molar mass}}=3.38\times 18g/mol=61g$

The maximum mass of water that could be produced by the chemical reaction is 61 grams.

6 0

3 years ago