Question

The total pressure for a mixture of N2O4 and NO2 is 1.5atm. If Kp = 7.1 at 25°C, calculate the partial pressure of each gas in the mixture. (HINT 1.5 = 2pNO2 + pN2O4) 2NO2 (g) = N2O4 (g)

Answer 1

Answer:

$N_{2} O_{4}$ : 0.5 atm and $N_{} O_{2}$ : 1 atm

Explanation:

In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.

It is given that $P_{total}$ = 1.5 atm

The mole fraction of each gas can be calculated in the following way:

$N_{2} O_{4}$ = moles of $N_{2} O_{4}$ ÷ total moles present = $\frac{1}{3}$

$N_{} O_{2}$ = moles of $N_{} O_{2}$ ÷ total moles present = $\frac{2}{3}$

Partial pressure of $N_{2} O_{4}$ : 1.5 × $\frac{1}{3}$ = 0.5 atm

Partial pressure of $N_{} O_{2}$ : 1.5 × $\frac{2}{3}$ = 1 atm

Hope that answers the question, have a great day!