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Nata [24]
4 years ago
14

Solve inequality and graph solution 3>4x-1

Mathematics
1 answer:
UkoKoshka [18]4 years ago
6 0

Answer: x < 1

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Divide<br> 4^2 divided by 4^6 =
alekssr [168]

Answer:

<h2>0.00390625 / 4^{-4} </h2>

Step-by-step explanation:

so you are saying do:

4^{2} /4^{6} which is 16 /4096

16/4096=0.00390625

<u>another way you can do this is</u>

4^{2} /4^{6}

just subtract the powers

2-6=-4

so the answer is 4^{-4}

3 0
3 years ago
Read 2 more answers
Draw and label ray RT
Keith_Richards [23]
You need a picture to lable and draw it so we can awnser your question
6 0
3 years ago
Please look at picture attached! i will mark you brainlyest if right!
katrin2010 [14]
Amp is the number in front of sine so its 1/2 aka D :)
8 0
2 years ago
Please help anyone and explain please
umka2103 [35]

So if you distribute 4 in the first parentheses, you get 12x+20y+8z.

Then you distribute 3 in the second parentheses. You'll get 3x-3z. That all equals 12x+20y+8z+3x-3z.

Now you have to start combining numbers with the same variable. Start with x. 12x+3x is 15x.

y has no other common variable, it's left alone.

8z-3z is 5z

All together now with the numbers in simpler form, the equation is 15x+20y+5z

Jenna's would be the right answer because when you distribute 5 in her answer you get 15x+20y+5z

5 0
3 years ago
Read 2 more answers
Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ
bixtya [17]

Answer:

AB=2\sqrt{ab}

Step-by-step explanation:

From figure,

OA=a,  \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)

In triangle OO'D

  (OO')^2=(OD)^2+(O' D)^2

\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]

Hence, AB=2\sqrt{ab}

6 0
3 years ago
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