A fusion reaction can be regarded as the type of reaction that occurs where two lighter elements come together in a type of reaction giving rise to a heavier/more massive element.
A fusion reaction always creates a more massive atomic nucleus (option c).
When the two lighter nuclei comes together in a reaction, a more heavier/massive nucleus is formed but its mass will still be less than the combined mass of the two reactant nuclei.
This also indicates that the left over mass may have been released as energy.
Learn more: brainly.com/question/18175586
Answer:
The number is mostly related to the mass or the weight of the element.
Explanation:
Answer:
ok.. what is your question??? confused
Answer:
You could rephrase this to make more sense? You could say “Mary me please!” This is a complete sentence. It has a verb and noun making it a full sentence. “Marry” is your verb and your noun is “me” I hope this helped have a good day! :) Please mark me the brainliest?
Answer: The distance is slightly less than 3.5 m
Explanation: assuming wall and target are the same thing, and the bullet has constant velocity, the bullet will travel 7 m in half a second, so half that distance is 3.5 m.
In reality, the bullet is decelerating (at an unknown rate) so the distance is slightly less than 3.5 m.
There is also a vertical velocity component, which means it hits the target/wall at an angle. The trajectory is such that it hits the wall above the shooter because the ricochet hits at ~the level at which it left the firearm.
If the wall was absent, the bullet would have described a parabola which brough it back to the initial level after 7m. This could be calculated, but it means that the actual distance between the shooter and the wall is slightly less than 3.5 m
In addition, the collision with the wall is not 100% elastic, so the velocity aftercthe ricochetvis further reduced.
A calculation would be complex because these confounding factors are not completely independent of each other, but all reduce the average velocity and therefore the distance.
Therefore it is only possible to say that the distance was somewhat less than 3.5 m
