That's kind of a ponderous way to describe it, but your 'X' represents
the absolute temperature of the ideal gas.
Answer:

Explanation:
In multiplication and division problems, the answer can have no more significant figures than the number with the fewest significant figures.
A calculator gives the result:

163.8 has four significant figures.
8.64 has three significant figures.
You must round to three significant figures.
That is, you drop all the digits to the right of the 9 — the red line in Fig. 1 below. You are rounding to the nearest tenth.
To round a number to the nearest tenth, you look at the digit in the hundredths place (7). See Fig. 2.
If the digit to be dropped is greater than 5 or is 5 followed by at least one non-zero digit, you add 1 to the number in the tenths place (Fig. 3).
Here's how you do it.
- The digit in the hundredths place is 5 followed by non-zero digits.
- Add 1 to the digit in the tenths place (9).
- ⁹/₁₀ + ⅒ = ¹⁰/₁₀ = 1 + ⁰/₁₀ = 1.0
The tenths digit becomes 0 and the ones digit increases from 8 to 9.

The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
<h3>What is Limiting reagent ?</h3>
The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
Given chemical equation in balanced form ;
2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).
According to the Chemical equation ;
- The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.
But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
- 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react
As 80 g NaOH produces 106 g of Na₂CO₃.
Therefore 5 g NaoH will produce ;
106 / 80 x 5 = 6.625 g
Learn more about limiting reagent here ;
brainly.com/question/11848702
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Earth orbits the sun in a imaginary plane called ecliptic
Homogeneous mixtures.
Hope this helps.