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Hatshy [7]
3 years ago
12

Determine the empirical and molecular formulas for a compound that has 10 pa a molar mass of 300 g/mol, and is 60.0% C, 12% H, a

nd 28% N by composition.​
Chemistry
1 answer:
nignag [31]3 years ago
3 0

Explanation:

the empirical formula is correct but I didn't got the question properly

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A student is determining the density of an unknown metal with a mass of 32.56 g. The student partially fills a graduated cylinde
xenn [34]

Answer:

The metal is Tin (Sn)

Explanation:

The following data were obtained from the question:

Mass of metal = 32.56 g

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Next, we shall determine the volume of the metal. This is illustrated below:

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water )

Volume of metal = 20.44 – 14.78

Volume of metal = 5.66mL

Next, we shall determine the density of the metal.

Density of a substance is defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance is expressed as:

Density = Mass / volume

With the above formula, we can obtain the density of the metal as follow:

Mass of metal = 32.56 g

Volume of metal = 5.66mL

Density =.?

Density = Mass /volume

Density = 32.56g/5.66mL

Density of the metal = 5.75g/mL

Comparing the density of the metal with standard density of elements, the metal is Tin (Sn)

4 0
3 years ago
What do dwarf planets, asteroids, and comets have in common
adell [148]

Answer:

their all small and arent considered planets

hope this could help

Explanation:

6 0
2 years ago
Read 2 more answers
How many molecules make up 8.41 moles of Ca2(SO3)?
sammy [17]

Answer:

<h3>5.06282 × 10²⁴ molecules</h3>

Explanation:

The number of molecules of Ca2(SO3) can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 8.41 × 6.02 × 10²³

We have the final answer as

<h3>5.06282 × 10²⁴ molecules</h3>

Hope this helps you

3 0
2 years ago
If you have a 1.0 L buffer containing 0.208 M NaHSO3 and 0.134 M Na2SO3, what is the pH of the solution after addition of 50.0 m
Vlada [557]

Answer:

pH = 7.233

Explanation:

Initially, the buffer contains 0.208 moles of NaHSO₃ and 0.134 moles of Na₂SO₃.

NaHSO₃ reacts with NaOH thus:

NaHSO₃ + NaOH → Na₂SO₃ + H₂O

50.0 mL of 1.00 M NaOH are:

0.0500L × (1mol / 1L) = 0.0500moles of NaOH added. That means after the addition are produced  0.0500moles of Na₂SO₃ and consumed 0.0500moles of NaHSO₃. That means final moles of the buffer are:

NaHSO₃: 0.208 mol - 0.050 mol = <em>0.158 mol</em>

Na₂SO₃: 0.134 mol + 0.050 mol = <em>0.184 mol</em>

<em> </em>

As pKa of this buffer is 7.167, it is possible to use H-H equation to find pH, thus:

pH = pKa + log₁₀ [Na₂SO₃] / [NaHSO₃]

pH = 7.167 + log₁₀ [0.184] / [0.158]

<em>pH = 7.233</em>

6 0
3 years ago
Argon, Ar, is a noble gas. How many miles of argon are in 200 gram sample of argon.? (Answer rounded to the ones place)
tatuchka [14]

The answer is 39.948 g/mol so rounded to the nearest ones would be 40.00 g/mol.

3 0
3 years ago
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