Answer:
D. 3.3 x 10^24
Explanation:
In a number representing a measurement, the significant figure are those digits that have a meaningful contribution to specify the resolution of the measurement.
When a number is written in scientific notation, it is written as:
where
m is the base
n is the exponent
When a number is written in this form, the number of significant figures is the number of digits contained in .
In this problem, our number is initially written as
We see that here "m" contains 4 digits, so here we have 4 significant figures.
In order to reduce it to 2 significant figures, we have to rewrite 3.311 as 3.3, therefore the new number will be:
Which is option D.
Answer:
I think it may be C because Newton's second law of motion states that the acceleration of an object equals the net force acting on the object divided by the object's mass.
There's also a possibility of B as well because the Law of force and acceleration but im not sure
Answer:
Even-number fatty acids such as palmitate undergoes complete β-oxidation in the liver motochondria to CO₂ because the product, acetyl-CoA can enter the TCA cycle.
Oxidation of odd-number fatty acids such as undecanoic acid yields acetyl-CoA + propionyl-CoA in their last pass. Propionyl-CoA requires additional reactions including carboxylation in order to be able to enter the TCA cycle.
The reaction CO2 + propionyl-CoA ----> methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, a biotin-containing enzyme, which is inhibited by avidin. Palmitate oxidation however, does not involve carboxylation.
Explanation:
Even-number fatty acids such as palmitate undergoes complete β-oxidation in the liver motochondria to CO₂ because their oxidation product, acetyl-CoA, can enter the TCA cycle where it is oxidized to CO₂.
Undecanoic acid is an odd-number fatty acid having 11 carbon atoms. Oxidation of odd-number fatty acids such as undecanoic acid yields a five -carbon fatty acyl substrate for their last pass through β-oxidation which is oxidized and cleaved into acetyl-CoA + propionyl-CoA. Propionyl-CoA requires additional reactions including carboxylation in order to be able to enter the TCA cycle. Since oxidation is occuring in a liver extract, CO₂ has to be externally sourced in order for the carboxylation of propionyl-CoA to proceed and thus resulting in comlete oxidation of undecanoic acid.
The reaction CO2 + propionyl-CoA ----> methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, a biotin-containing enzyme. The role of biotin is to activate the CO₂ before its tranfer to the propionate moiety. The addition of the protein avidin prevents the complete oxidation of undecanoic acid by binding tightly to biotin, hence inhibiting the activation and transfer of CO₂ to propionate.
Palmitate oxidation however, does not involve carboxylation, hence addition of avidin has no effect on its oxidation.
The final temperature (°C) of the air at this elevation is 326.3K.
<h3>How to calculate temperature?</h3>
The temperature of a gas can be calculated using the combined gas law equation as follows:
P₁V₁/T₁ = P₂V₂/T₂
Where;
- P₁ = initial pressure
- V₁ = initial volume
- T₁ = initial temperature
- P₂ = final pressure
- V₂ = final volume
- T₂ = final temperature
According to this question, 1.20L weather balloon on the ground has a temperature of 25.0°C and is at atmospheric pressure (1.00 atm). When it rises to an elevation where the pressure is 0.730 atm, then the new volume is 1.80L. The final temperature can be calculated thus:
1 × 1.2/298 = 0.730 × 1.8/T₂
0.004027T = 1.314
T = 326.3K
Therefore, 326.3K is the final temperature of the balloon.
Learn more about combined gas law at: brainly.com/question/2441080
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