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harkovskaia [24]

3 years ago

7

Raul eats 1/4 of candy bar

1 answer:

dexar [7]3 years ago

3 0

What is the question

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The area of a circle with a radius of 26 inches

exis [7]

Answer:

2,123.7 square inches

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need help breaking this down

sergeinik [125]

Answer:

see explanation

Step-by-step explanation:

Given

2cosΘ - $\sqrt{2}$ = 0 ( add $\sqrt{2}$ to both sides )

2cosΘ = $\sqrt{2}$ ( divide both sides by 2 )

cosΘ = $\frac{\sqrt{2} }{2}$

Since cosΘ > 0 then Θ is in first and fourth quadrants, hence

Θ = $cos^{-1}$ ( $\frac{\sqrt{2} }{2}$ ) = $\frac{\pi }{4}$

OR

Θ = 2π - $\frac{\pi }{4}$ = $\frac{7\pi }{4}$

solutions are Θ = $\frac{\pi }{4}$ , $\frac{7\pi }{4}$

3 0

2 years ago

Read 2 more answers

Gwar [14]

$\\ \bull\sf\longmapsto -9+(-4)=-9-4=-13$

$\\ \bull\sf\longmapsto +3-(-5)=3+5=8$

$\\ \bull\sf\longmapsto 2\times 2=4$

$\\ \bull\sf\longmapsto 36+4=40$

$\\ \bull\sf\longmapsto 5\times 7=35$

$\\ \bull\sf\longmapsto 8(9)=72$

$\\ \bull\sf\longmapsto -4+(-2)=-4-2=-6$

$\\ \bull\sf\longmapsto 3-(-6)=3+6=9$

$\\ \bull\sf\longmapsto -6(-3)=18$

$\\ \bull\sf\longmapsto -4+(-4)=-4-4=-8$

$\\ \bull\sf\longmapsto 5(7)=35$

$\\ \bull\sf\longmapsto 4-(-5)=4+5=9$

$\\ \bull\sf\longmapsto 4-3=1$

$\\ \bull\sf\longmapsto 10+5=15$

$\\ \bull\sf\longmapsto 3(8)=24$

7 0

2 years ago

Calculate the mode 5,10,12,4,6,11,13,5 show work

yaroslaw [1]

The answer for this question is 5 because 5 shows up the most. The mode is the number that shows up more often then any other numbers

7 0

3 years ago

Both circle A and circle B have a central angle measuring 50°. The area of circle A's sector is 36π cm2, and the area of circle

slega [8]

Answer:

A) 3/4

Step-by-step explanation:

Given: Both circle A and circle B have a central angle measuring 50°.

The area of circle A's sector is 36π cm2.

The area of circle B's sector is 64π cm2.

We know, area of the circle= $\pi r^{2}$

lets assume the radius of circle A be " $r_1$ " and radius of circle B be " $r_2$ "

As given, Area of circle A and B´s sector is 36π and 64π repectively.

Now, writing ratio of area of circle A and B, to find the ratio of radius.

⇒ $\frac{\pi r_1^{2} }{\pi r_2^{2} } = \frac{36\pi }{64\pi }$

Cancelling out the common factor

⇒ $\frac{r_1^{2} }{r_2^{2} } = \frac{36 }{64}$

⇒ $(\frac{r_1 }{r_2} )^{2} = \frac{36 }{64}$

Taking square on both side.

Remember; √a²= a

⇒ $(\frac{r_1 }{r_2} ) =\sqrt{ \frac{36 }{64}}$

⇒ $(\frac{r_1 }{r_2} ) = \frac{6}{8}$

⇒ $\frac{r_1 }{r_2} = \frac{3}{4}$

Hence, ratio of the radius of circle A to the radius of circle B is 3:4 or 3/4.

5 0

3 years ago