1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
murzikaleks [220]
2 years ago
11

In a famous experiment, Wöhler heated ‘inorganic’ ammonium cyanate in the absence of air. The only product of the reaction was ‘

organic’ urea, CO(NH2)2. No other products were formed in the reaction. What is the formula of the cyanate ion present in ammonium cyanate? A CNO– B CNO2– C CO– D NO– why A?
Chemistry
1 answer:
Soloha48 [4]2 years ago
5 0
<span>CO(NH2)2 the only product consists of 1 Carbon 1 Oxygen , 2 Nitrogen and 4 Hydrogen We are heating Ammonium Cyanate, Ammonium Ion NH4+ NH4+ consists of 1 Nitrogen 4 Hydrogen. Compare the reactant decomposed and product formed.

There should be 2 Nitrogen so Cyanate must contain one Nitrogen atom, one Carbon and one oxygen.</span>
You might be interested in
Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50Ti (5.3%). What is the average atomic
NNADVOKAT [17]

Hey there!:

Isotopes :                          abundance :

46 Ti                                       8.0%

47 Ti                                        7.8 %

48 Ti                                      73.4 %

49 Ti                                       5.5 %

50 Ti                                         5.3 %

Weighted average =   ∑ Wa * % / 100

Therefore:

( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =

4792.3 / 100

= 47.923 a.m.u


       Hope that helps!

7 0
2 years ago
2. Heat is:
nlexa [21]
A. Thermal energy good job
5 0
3 years ago
Read 2 more answers
42. Proton and electuron.
Sauron [17]

Answer:

Protons:

- positive

- aka cation

- in the nucleus along with the neutrons

Electrons:

- negative

- aka anion

- situated in the orbital shells/configuration levels (there are many names)

7 0
2 years ago
Is this an example of decomposition<br> 2CH4 + 402 → 2C02 + 4H2O
Molodets [167]

Answer:

Identify each equation as a composition reaction, a decomposition reaction, or neither.

Fe2O3 + 3 SO3 → Fe2(SO4)3

NaCl + AgNO3 → AgCl + NaNO3

(NH4)2Cr2O7 → Cr2O3 + 4 H2O + N2

Solution

In this equation, two substances combine to make a single substance. This is a composition reaction.

Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.

A single substance reacts to make multiple substances. This is a decomposition reaction.

Test Yourself

Identify the equation as a composition reaction, a decomposition reaction, or neither.

C3H8 → C3H4 + 2 H2

Explanation:

I hope I help :)))

5 0
3 years ago
What is the name of the process plants use to make the energy (food) they need?
scZoUnD [109]
The answer you looking for is D
8 0
2 years ago
Read 2 more answers
Other questions:
  • After Frank Palko was sentenced to death by the state of Connecticut, the Supreme Court ruled that
    15·2 answers
  • Which similarity did the Aztecs and ancient Egyptians share?
    8·2 answers
  • Which describes the role of carbon dioxide in photosynthesis?
    9·2 answers
  • The temperature at which a liquid becomes a solid is the:
    12·2 answers
  • Each particular chemical reaction cannot be expected to occur at identical rates.
    9·1 answer
  • What SI unit is used to measure the number of representative particles in a substance?
    12·1 answer
  • At constant volume, a tank of gas shows a pressure of 2500 atm at 290 K. The tank is then placed in a metal shed where the tempe
    11·1 answer
  • The nucleus of an atom is ___.​
    11·1 answer
  • Which one??........LMK
    13·1 answer
  • Read the given equation.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!