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murzikaleks [220]
3 years ago
11

In a famous experiment, Wöhler heated ‘inorganic’ ammonium cyanate in the absence of air. The only product of the reaction was ‘

organic’ urea, CO(NH2)2. No other products were formed in the reaction. What is the formula of the cyanate ion present in ammonium cyanate? A CNO– B CNO2– C CO– D NO– why A?
Chemistry
1 answer:
Soloha48 [4]3 years ago
5 0
<span>CO(NH2)2 the only product consists of 1 Carbon 1 Oxygen , 2 Nitrogen and 4 Hydrogen We are heating Ammonium Cyanate, Ammonium Ion NH4+ NH4+ consists of 1 Nitrogen 4 Hydrogen. Compare the reactant decomposed and product formed.

There should be 2 Nitrogen so Cyanate must contain one Nitrogen atom, one Carbon and one oxygen.</span>
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What is the physical state of element chromium
olga2289 [7]

Answer:

Solid metal.

Explanation:

At room temperature, Chromium (Cr), a transition metal, is a solid.

7 0
3 years ago
Using the formula velocity = distance/time, how fast does sound travel in air at 20 degrees C given a distance of 500 m and 3.92
mixas84 [53]

Answer:

B : 127m/s

Explanation:

= 500 ÷ 3.92

= 127.5

5 0
3 years ago
What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:
Margarita [4]

Answer:

108.6 g

Explanation:

  • 2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the <em>PV=nRT formula</em> to <u>calculate the number of nitrogen moles</u>:

  • P = 1.00 atm
  • V = 56.0 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 0 °C ⇒ 0 + 273.2 = 273.2 K

<u>Inputting the data</u>:

  • 1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K
  • n = 2.5 mol

Then we <u>convert 2.5 moles of N₂ into moles of NaN₃</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 2.5 mol N₂ * \frac{2molNaN_3}{3molN_2} = 1.67 mol NaN₃

Finally we <u>convert 1.67 moles of NaN₃ into grams</u>, using its <em>molar mass</em>:

  • 1.67 mol * 65 g/mol = 108.6 g
6 0
2 years ago
Pure titanium metal is produced by reaction titanium(IV) chloride with magnesium metal. The equation for the reaction is: TiCl4(
qaws [65]

Answer:

The answer to your question is 1.013 Kg

Explanation:

                     TiCl₄  +  2Mg   ⇒     2MgCl₂   +   Ti

mass of Mg = ?

mass of Ti = 1 kg

Process

1.- Calculate the molar mass of Magnesium and titanium (IV)

    Mg = 24.3 g x 2 = 48.6 g

    Ti = 48 g

2.- Write a proportion (rule of three)

                         48.6 g of Mg -------------  48 g of Ti

                           x                   -------------  1000 g of Ti

                           x = (1000 x 48.6) / 48

3.- Result

                 mass of Magnesium = 1012.5g

                                                    = 1.013 kg      

7 0
3 years ago
How many energy levels does this atom have
Bas_tet [7]

Answer:

i feel like it would be four

Explanation:

Srr if i was wrong

8 0
3 years ago
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