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Andru [333]
4 years ago
12

A compound contains 25.93% N and the rest is oxygen. What is the empirical formula for the compound?

Chemistry
1 answer:
Mnenie [13.5K]4 years ago
5 0

Answer: NO2

Explanation:

                                  N                                O

Divide each by its    25.93                       74.07

mass number              14                             16

                                     2                              4

Divide both by the       2                               2

smaller (i.e. 2)               1                                2

Therefore, the empirical formula = NO2

                                     

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The mixture of carbon dioxide and water tastes salt why​
vampirchik [111]

Answer:

When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air

Explanation:

6 0
3 years ago
Which of the following involves a change in physical properties only?
Mnenie [13.5K]

Answer: maybe mixing with an acid? They are all very similar

Explanation:

Maybe because the different acids have different atoms and molecules

5 0
3 years ago
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Calculate the molarity of 0.50 mol MgCl2 in 750 ml of solution.
Vedmedyk [2.9K]

Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.

Molarity :

It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .

It uses unit M or \frac{mol}{L}

It can be formulated as :

Molarity (\frac{mol}{L} ) = \frac{mole of solute (mol)}{volume of solution (L)}

Given : mol of MgCl₂ (solute ) = 0.50 mol

Volume of solution = 750 mL

Following steps can be done :

Step 1 ) To convert volume of solution from mL to L

1 L = 1000 mL

Volume of solution = 750 mL * \frac{1 L}{1000mL}

Volume of solution = 0.750 L

Step 2) To find molarity

Plugging mole of solute and volume of solution in molarity formula as :

Molarity = \frac{0.50 mol}{0.750 L }

Molarity = 0.67 \frac{mol}{L}

Hence molarity of MgCl₂ solution is 0.67 M

4 0
4 years ago
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Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.
Tema [17]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a: C sp^{2}  O sp^{2} .

Explanation : The sigma bonds in the 'a' position involves carbon atom which undergoes sp^{2} hybridisation and has sp^{2} orbitals of carbon and as well as oxygen atoms involved in the bonding.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O sp^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has sp^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C sp^{3} O sp^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of sp^{3} hybridized bonds.

Answer 5) Bond d:   C sp^{3}  C sp^{3}

Explanation : The bonding involved at the position of 'd' involves two carbon atoms. Therefore, they undergo sp^{3} hybridization. The orbitals involved in this hybridization are also sp^{3}.

Answer 6) Bond e:  C1 containing O sp^{2}    C2 sp^{3}

Explanation : The bonding at the 'e' position involves two carbon atoms on is containing oxygen with double bonds and the C2 carbon atom. The carbon containing oxygen has sp^{2} hybridized orbitals involved in the bonding; whereas C2 carbon ha sp^{3} orbitals.

6 0
4 years ago
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Under which circumstances is the enthalpy of a reaction a positive value?
uranmaximum [27]
The answer Is D

Hope I helped! ( Smiles )
5 0
3 years ago
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