Answer:
When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air
Explanation:
Answer: maybe mixing with an acid? They are all very similar
Explanation:
Maybe because the different acids have different atoms and molecules
Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.
Molarity :
It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .
It uses unit M or 
It can be formulated as :

Given : mol of MgCl₂ (solute ) = 0.50 mol
Volume of solution = 750 mL
Following steps can be done :
Step 1 ) To convert volume of solution from mL to L
1 L = 1000 mL

Volume of solution = 0.750 L
Step 2) To find molarity
Plugging mole of solute and volume of solution in molarity formula as :


Hence molarity of MgCl₂ solution is 0.67 M
Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.
Answer 1) σ Bond a: C
O
.
Explanation : The sigma bonds in the 'a' position involves carbon atom which undergoes
hybridisation and has
orbitals of carbon and as well as oxygen atoms involved in the bonding.
Answer 2) π Bond a: C has π orbitals and O also has π orbitals.
Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.
Answer 3) Bond b: O
H has only S orbital involved in bonding.
Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has
hybridized orbitals and S orbital of hydrogen involved in the bonding.
Answer 4) Bond c: C
O
Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of
hybridized bonds.
Answer 5) Bond d: C
C 
Explanation : The bonding involved at the position of 'd' involves two carbon atoms. Therefore, they undergo
hybridization. The orbitals involved in this hybridization are also
.
Answer 6) Bond e: C1 containing O
C2 
Explanation : The bonding at the 'e' position involves two carbon atoms on is containing oxygen with double bonds and the C2 carbon atom. The carbon containing oxygen has
hybridized orbitals involved in the bonding; whereas C2 carbon ha
orbitals.
The answer Is D
Hope I helped! ( Smiles )