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Andru [333]
3 years ago
12

A compound contains 25.93% N and the rest is oxygen. What is the empirical formula for the compound?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer: NO2

Explanation:

                                  N                                O

Divide each by its    25.93                       74.07

mass number              14                             16

                                     2                              4

Divide both by the       2                               2

smaller (i.e. 2)               1                                2

Therefore, the empirical formula = NO2

                                     

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179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g
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Answer:

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Explanation:

Generally the change in temperature of water is evaluated as

                \Delta T = T_2 -T_1

Substituting 16.1°C for T_1 and 27.4°C for T_2

                \Delta T = 27.4 - 16.1

                       =11.3^oC

Generally the change in temperature of  unknown compound is evaluated as

                  \Delta T_u = T_3 -T_2

Substituting 27.4°C for T_2 and 94.3°C for T_3

                                    \Delta T = 94.3 - 27.4

                                           =66.9^oC

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

               H_w = mc_w \Delta T

Substituting 179.1 g  for m , 4.18 J/g.C for c_w(specific heat of water)

             H_w = 4.18 * 179.1 * 11.3

                   = 8459.6J

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

                    H_u = m_uc_u \Delta T_u

By conservation of energy law

       Heat lost  = Heat gained  

Substituting 306.9 g  for m_u , 8459.6J for H_u

           8459.6 = 306.9 * c_u * 66.9

  Therefore     c_u = \frac{8459.6}{308.9 *66.9}

                           =0.412J/g \cdot C

                   

4 0
3 years ago
The gas in a balloon has a volume of 2 Lat a temperature of 301 K. What will be the final temperature (in K) when the volume exp
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Answer:

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Explanation:

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From Charles law, we know that;

V1/T1 = V2/T2

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V1 is the initial volume

T2 is the final temperature

V2 is the final volume

We are given;

V1 = 2 L

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V2 = 8.5 L

Thus, making T2 the subject, we have;

T2 = V2•T1/V1

Plugging in the relevant values;

T2 = 8.5 × 301/2

T2 = 1279.25 K

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