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Andru [333]
3 years ago
12

A compound contains 25.93% N and the rest is oxygen. What is the empirical formula for the compound?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer: NO2

Explanation:

                                  N                                O

Divide each by its    25.93                       74.07

mass number              14                             16

                                     2                              4

Divide both by the       2                               2

smaller (i.e. 2)               1                                2

Therefore, the empirical formula = NO2

                                     

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             Option-B (Carbon and Silicon)

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                  Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

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Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 K  +  Cl₂    →     KCl

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A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid
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<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

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Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

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<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

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Mass of HA = 0.462 g

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0.00512 = 0.462/ Molar mass

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Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

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