David's total income is ($8/hr)x + ($11/hr)y.
This problem requires us to write and solve an inequality:
8x + 11(15)<$200
Solving for x: 8x < $200-$165, or 8x < $35. Strictly speaking, x = 4.375 hrs, but if we assume that David must work an integer # of hours, then x=5 full hours.
Answer:
The answer is c: y = 35x + 1000
Step-by-step explanation:
Jamie starts off with 1000 which means that no matter how much more money she adds to the account she still has to add the 100 she already has. Then she is adding $35 per month so it would be positive 35 so the correct equation is
35x +1000
Here I have included 3 methods: Differentiating, Integrating and factorize
Differentiating:
Integrating:
Factorise:
Answer:
You have to define when the power should be pushed up using the 'For' statement and let an impulse be sent to the CPU to increase power by 15%
Step-by-step explanation:
We use certain functions in writing computer programs.
For the 'For' statement ; we can define conditions. First Elana would define at what point does she want the player power to get the best power.
For example if she defines that when the player has played for 2hours return an integer 1 for instance.
This value returned will now send a pulse to the CPU to increase its power to 15%.
If the player plays for further 1hour she can define the count to be 10 and so send another pulse to the CPU to increase the processing power by additional 15%
Answer:
(14,-4)(-4,-4)
Step-by-step explanation:
5+9=14
5-9=-4
