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marusya05 [52]
3 years ago
8

Do chemical equations with no reaction still have to be balanced

Chemistry
1 answer:
dangina [55]3 years ago
5 0

Answer:

The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.

Explanation:

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Describe how you think the tiny dust particles acquired a charge.
miskamm [114]
Whenever they move, they get a charge from the moment. <span />
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2 years ago
Describe how to properly measure the volume of a liquid.
marusya05 [52]
The best way to measure it usually is to use a beaker or graduated cylinder. 
5 0
3 years ago
Read 2 more answers
Chemistry help!<br><br><br><br><br>Zoom in to see better!! ​
Julli [10]

Answer:

2.5 moles of Al

Explanation:

We'll begin by calculating the number of mole in 127 g of Al₂O₃. This can be obtained as follow:

Mass of Al₂O₃ = 127 g

Molar mass of Al₂O₃ = 101.961 g/mol

Mole of Al₂O₃ =?

Mole = mass / molar mass

Mole of Al₂O₃ = 127 / 101.961

Mole of Al₂O₃ = 1.25 mole

Finally, we shall determine the number of mole of Al that reacted. This can be obtained as follow:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted to produce 2 moles of Al₂O₃.

Therefore, Xmol of Al will react to produce 1.25 moles of Al₂O₃ i.e

Xmol of Al = (1.25 × 4)/2

Xmol of Al = 2.5 moles.

Thus, 2.5 moles of Al is needed for the reaction.

4 0
2 years ago
The work done depends upon the --------------applied and the -------------- produced​
Deffense [45]

Answer:

The work done depends upon the <u> Force</u> applied and <u>Displacement</u> produced.

Explanation:

Definition: Work is said to be on a body only if a force acting on it causes a displacement in its direction .

In other words we can say it is the product of force and displacement

Formula:

Work = Force\times Displacement\ cos \theta

Unit:

The unit of work is Joule.

So, work depends on the force applied and the displacement caused by the applied force.

If force is applied and there is no displacement, then work is 0 .

Example: Pushing a wall does no work.

Work is positive if force applied and displacement is in same direction.

Work is negative if force applied and displacement is in opposite direction.

3 0
2 years ago
A particle of mass 2.0 kg moves under the influence of the force F(x)=(-5x^2+7x)~\text{N}F(x)=(−5x ​2 ​​ +7x) N. If its speed at
Brums [2.3K]

Answer:

The speed of the particle at x = 4.0 m is 13.66 m/s

Explanation:

The work done by this force between the two points above is given by

W = ∫ F dx

W = ∫⁴₋₄ (-5x² + 7x) dx

W = [(-5x³/3) + (7x²/2)]⁴₋₄

W = [(-5(4³)/3) + (7(4²)/2)] - [(-5(-4)³)/3) + (7((-4)²)/2)] = (-50.6667) - (162.6667) = (- 213.33 J)

Kinetic energy at -4.0 m

At this point, v = 20 m/s

K.E = mv²/2 = 2 × 20²/2 = 400 J

To obtain the kinetic energy at 4 m,

We apply the work-energy theorem which mathematically translates to

The work done in moving a particle from one point to another = Change in kinetic energy of the particle between those two points

W = ΔK.E

Work done between x = - 4m and x = 4 m is - 213.33 J

Hence, ΔK.E = -213.33 J

Change in kinetic energy of the particle between x = - 4m and x = 4m is ΔK.E

ΔK.E = (Kinetic energy at x = 4m) - (kinetic energy at x = - 4m)

- 213.33 J = (mv²/2) - 400

mv²/2 = -213.33 + 400 = 186.67 J

2v² = 2 × 186.67

v² = 186.67

v = 13.66 m/s.

5 0
3 years ago
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