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Vsevolod [243]
4 years ago
15

The first three terms of a Fibonacci sequence are n 3n 4n find the sixth term I FB the sequence

Mathematics
1 answer:
Amiraneli [1.4K]4 years ago
3 0

Answer:

<h2>18n</h2>

Step-by-step explanation:

In the Fibonacci sequence In mathematics, the Fibonacci numbers, commonly denoted Fn, form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1.

Given data

First term= n

second term = 3n

third term = 4n

According to Fibonacci sequence the fourth term is

F4= F2 + F3\\F4=3n+ 4n= 7n

the Fifth term is

F5= f3 + f4\\f5= 4n+7n= 11n

hence  the sixth term is

F6= F4+F5\\   F6= 7n+11n= 18n

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Svetradugi [14.3K]

Answer: 10 and -4

Step-by-step explanation:

3x - 2 Plug in 4 for x

3(4) - 2 = 12 - 2 = 10

5x + 6. Plug in -2 for x

5(-2) + 6 = -10 + 6 = -4

8 0
4 years ago
In VWX x=41 cm v=17 cm and W=134 degrees. Find the length of w, the the nearest centimeter
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Answer:

54

Step-by-step explanation:

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3 years ago
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Given p(x) = x^3-6x^2+32 when it is divided by  x - 4, the quotient gives

x^2-2x-8

Q(x) = P(x)/d(x)

x^3-6x^2+32/x- 4  =  x^2-2x-8

Factorizing the quotient

x^2-2x-8

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)

8 0
3 years ago
Two particles are projected simultaneously towards each other from opposite ends of a straight
Anit [1.1K]

Answer:

The problem with this question is that it is missing an important number, which is the length of the tube. Assuming that the tube is 10 meters long (=1,000 centimeters long)

time (in        distance traveled         distance traveled       distance

seconds)     by particle A in cms     by particle B in cms    between both

                                                                                              particles in cms

1                               97                            49                     854

2                               93                            47                     714

3                               89                            45                     580

4                               85                            43                     452

5                               81                            41                     330

6                               77                            39                     214

7                               73                            37                     104

8                               69                            35                     0

   

After 8 seconds both particles should meet. Particle A traveled 664 centimeters and particle B traveled 336 centimeters.    

8 0
3 years ago
Beth had 1 yard of ribbon. she used 1/5 yard for a project. She wants to divide the rest of the ribbon into pieces 1/10 yard lon
likoan [24]
1 - (1/5) = 4/5 yards of ribbon.
(4/5) / (1/10) = 8 Pieces of 1/10 Yard Long Ribbons

Hope that Helped you.
4 0
3 years ago
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