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Paul [167]
3 years ago
7

Given triangle STU equal to KLM complete each of the following statements TU= KM= LK=

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

TU = LM

KM = SU

LK = TS

Step-by-step explanation:

It is given that ΔSTU ≅ ΔKLM

Since, the corresponding parts of congruence triangle are equal,

The corresponding sides TU of ΔSTU and LM of ΔKLM are equal.

The corresponding sides KM of ΔKLM and SU of ΔSTU are equal.

The corresponding sides LK of ΔKLM and TS of ΔSTU are equal.

Hence,

TU = LM

KM = SU and

LK = TS

wlad13 [49]3 years ago
3 0

Answer:

Notice that \triangle STU \cong \triangle KLM, by given,

From this congruence, we deduct several congruences between corresponding elements.

TU \cong LM

KM \cong SU

LK \cong TS

\angle M \cong U

\angle T \cong \angle L\\\angle UST \cong \angle MKL

\triangle UST \cong \triangle MKL

\triangle TUS \cong \triangle LMK

Notice that elements correspond each other according to the given congruence between triangles.

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MatroZZZ [7]

Answer:

a)Slope: \hat \beta_1 =\frac{7625.9}{1248.9}=6.106

Intercept: \hat \beta_o = 157.955 -6.106 (69.686)=-267.548

b) r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657  

And the determination coeffecient is r^2 = 0.657^2 =0.432  

Step-by-step explanation:

Data given and definitions

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"    

When we conduct a multiple regression we want to know about the relationship between several independent or predictor variables and a dependent or criterion variable.  

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

\sum Y_i =17375 , \sum X_i = 7665.5

Part a

The slope is given by this formula:

\hat \beta_1 =\frac{\sum (x-\bar x) (y-\bar y)}{\sum (x-\bar x )^2}

If we replace we got:

\hat \beta_1 =\frac{7625.9}{1248.9}=6.106

We can find the intercept with the following formula

\hat \beta_o = \bar y -\hat \beta_1 \bar x

We can find the average for x and y like this:

\bar X=7665.5/110 =69.686, \bar y= 17375/110=157.955

And replacing we got:

\hat \beta_o = 157.955 -6.106 (69.686)=-267.548

Part b

In order to calculate the correlation coefficient we can use this formula:  

r=\frac{\sum (x-\bar x)(y-\bar y) }{\sqrt{[\sum (x-\bar x)^2][\sum(y-\bar y)^2]}}  

For our case we have this:  

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

So we can find the correlation coefficient replacing like this:

r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657  

And the determination coeffecient is r^2 = 0.657^2 =0.432  

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Answer:

The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:

x + 2x < 50 ............................ (2)

We can now solve for x as follows:

3x + < 50

x < 50 / 3

x < 16.67

Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

y < 2 * 16.67

y < 33.33

Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

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