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USPshnik [31]
3 years ago
11

What tupe of group number is 3/4. A. Real, B. Rational, C. Irrational, D. Integer, E. Whole, F. Counting

Mathematics
2 answers:
sveta [45]3 years ago
8 0

B: Rational

i think it is though

otez555 [7]3 years ago
8 0

Answer:

The answer is B, Rational!!!XD


Hope this helped!!!


Also, can I get brainliest?

Step-by-step explanation:


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patriot [66]

Answer:

y = 3/2 x + 3

Step-by-step explanation:

2/3 x + y = -14/3

y = -2/3 x − 14/3

The slope of this line is -2/3.  So the perpendicular slope is the opposite of the inverse:

m = -1 / (-2/3)

m = 3/2

We know the slope of the line and a point on the line, so using point-slope form:

y − 0 = 3/2 (x − (-2))

Simplifying into slope-intercept form:

y = 3/2 (x + 2)

y = 3/2 x + 3

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2 years ago
Evaluate<br> 11<br> % of <br> 953.23<br> m<br> Give your answer rounded to 2 DP.
Akimi4 [234]

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{11\% of 953.23}}{\left( \cfrac{11}{100} \right)953.23}\implies 104.86

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2 years ago
Evaluate when a=-6, b= 5, C= -2:
cluponka [151]

Answer:

c 81

Step-by-step explanation:

6 0
3 years ago
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Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

4 0
3 years ago
AAAAAAAAAAAAAA ORRRRRRRR DDDDDDDDDD
blondinia [14]
Think it’s A just because it’s actually decaying rather than being from decayed to up like B, C, and D( I don’t know how to explain it, sorry) I’m not sure however !
7 0
2 years ago
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