All categories

3 years ago

What tupe of group number is 3/4. A. Real, B. Rational, C. Irrational, D. Integer, E. Whole, F. Counting

Mathematics

2 answers:

sveta [45]3 years ago

8 0

B: Rational

i think it is though

otez555 [7]3 years ago

8 0

Answer:

The answer is B, Rational!!!XD

Hope this helped!!!

Also, can I get brainliest?

Step-by-step explanation:

You might be interested in

Find three solutions to the equation 2x+3y=12

aleksley [76]

Answer:

if x = 3, then y = 2

if x = 0, then y = 4

if x = 6, then y = 0

3 0

2 years ago

At Silver Gym, membership is $20 per month, and personal training sessions are $35 each. At Fit Factor, membership is $40 per mo

Molodets [167]

Answer:

125

Step-by-step explanation:

5 0

3 years ago

A pencil at a stationery store costs $1, and a pen costs $1.50. Stefan spent $7 at the store. He bought a total of 6 items. Whic

LekaFEV [45]

Well, the first one, I have never worked with before so I'm sry but I can't help you with that one. 3y + x = 4 (x=1) 2y - x = 6 (x=8)

4 0

3 years ago

Verify the following <br> i.[ -3/4]3 = -27/64<br> ii. [-2/3]6 = 64/ 729

Juliette [100K]

Answer:

The relationships are correct and valid

Step-by-step explanation:

The correct question is as follows;

Verify the following

i.[ -3/4]^3 = -27/64

ii. [-2/3]^6 = 64/ 729

We have the solution as follows;

i) we have;

(-3/4)^3

That means ;

-3^3 = -3^3 = -27

4^3 = 64

so;

(-3/4)^3 = -27/64

ii) (-2/3)^6

(-2)^6 = 64

3^6 = 729

Thus;

(-2/3)^6 = 64/729

4 0

3 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

6 0

3 years ago