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ELEN [110]
4 years ago
14

Write an expression of the area of a square with the side length s

Mathematics
1 answer:
PtichkaEL [24]4 years ago
3 0

Answer:

s²

Step-by-step explanation:

Since you can't substitute you say area of square = side x side = s * s = s²

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Geometric Shapes - Part 1
Softa [21]

Answer:

x = 54, so the vertical angles are 110°.

Step-by-step explanation:

2x + 2 = 3x - 52

2  = x - 52

x = 54

2(54) + 2 = 108 + 2 = 110

3(54) - 52 = 162 - 52 = 110

3 0
3 years ago
Two trains are moving towards each other. One train moves at a speed of 50 mph, and the other train travels at 60 mph. How soon
Margaret [11]
I think that they will meet in 3 hours and 11 min but I’m not too sure
4 0
3 years ago
Read 2 more answers
Find the length indicated. find CE
torisob [31]
Okay, to find length CE, your going to know the value of <em>x</em>. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
4x+73=37+x
you can choose one of four ways to continue, but I will choose to subtract x
3x+73=37
Subtract 73 from both sides of the equal sign
3x=-36
divide by 3 on both sides of the equal sign to get the value of x
x=-12

Now, plug in -12 for x in length CE to get -12+26=14
6 0
4 years ago
A total of 430 tickets were sold for the school play . They were either adult tickets or student tickets . There were 70 fewer s
Maurinko [17]
So first we assume that half is adult and have is student.

So
215 adult  215 student

Now since it said they were 70 less student tickets than adult tickets we subtract 70.
215 - 70 = 145

Now we add the 70 we subtracted from student tickets to the adult tickets.
215 + 70 = 285

So there were 
285 adult tickets sold and 145 student tickets sold

I hope this helped. Have a great day!
6 0
3 years ago
The solutions to the inequality y&lt;-x+1 are shaded on the graph. Which point is a solution?
suter [353]
Answer: 
B) (3, –2)

Explanation: 
The inequality is y ≤ –x + 1
There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.

I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C. 
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign. 
Try it in the inequality: 
y ≤ –x + 1 
–2 ≤ –3 + 1 
–2 ≤ –2 yes this checks out.
9 0
4 years ago
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