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ser-zykov [4K]
3 years ago
12

1) Air modeled as an ideal gas enters a well-insulated diffuser operating at steady state at 270 K with a velocity of 180 m/s an

d exits with a velocity of 48.4 m/s. For negligible potential energy effects, determine the exit temperature, in K.
Physics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

Explanation:

Kinetic energy of a gas molecule = 3/2 k T

1/2 m v² = 3/2 k T

v² ∝ T

(v₁ / v₂)² = T₁ / T₂

( 180 / 48.4 )² = 270 / T₂

13.83  = 270 / T₂

T₂ = 19.52 K .

Exit temp = 19.52 K .

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A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east.
Anna71 [15]

Answer:

Time, t = 12 minutes

Explanation:

It is given that,

A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east. Let west direction is negative and east direction is positive. The displacement of the cyclist is :

d=16-8+8-32+11.2=-4.8\ km

d = 4800 m

Let us assumed that the average speed of the cyclist is, v = 24 km/h = 6.66667 m/s

Let t is the time taken by the cyclist to complete the trip. The velocity of an object is given by :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{4800\ m}{6.66667\ m/s}

t = 719.99 seconds

t = 720 seconds

or

t = 12 minutes

So, the time taken by the cyclist to complete the trip is 12 minutes. Yes, the time taken by the cyclist to complete the trip is reasonable. Hence, this is the required solution.                                      

7 0
3 years ago
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
Calculate the acceleration of a 90-kg skydiver with a net force of -883 N
Helen [10]
F=ma, in this case your force=-883 N and mass = 90 kg. F/m=a therefore acceleration=-883/90=-9.81 m/s/s
6 0
3 years ago
Ultraviolet light of wavelength 270 nm strikes a metal whose work function is 2.3 eV.What is the shortest de Broglie wavelength
soldier1979 [14.2K]

Answer:

The shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

Explanation:

Given;

wavelength of ultraviolet light, λ = 270 nm

work function of the metal, φ = 2.3 eV = 2.3 x 1.602 x 10⁻¹⁹ J = 3.685 x 10⁻¹⁹ J

The energy of the ultraviolet light is given by;

E = \frac{hc}{\lambda}\\\\E = \frac{(6.626*10^{-34} )(3*10^{8}) }{270*10^{-9} }\\\\E = 7.362 * 10^{-19} \ J

The energy of the incident light is related to kinetic energy of the electron and work function of the metal by the following equation;

E = φ  + K.E

K.E = E - φ

K.E = (7.362 x 10⁻¹⁹ J) - (3.685 x 10⁻¹⁹ J )

K.E = 3.677 x 10⁻¹⁹ J

K.E = ¹/₂mv²

mv² = 2K.E

velocity of the electron is given by;

V = \sqrt{\frac{2K.E}{m} }\\\\V =  \sqrt{\frac{2(3.677*10^{-19}) }{9.1*10^{-31} } }\\\\V = 8.99*10^{5}  \ m/s

the shortest de Broglie wavelength for the electrons is given by;

\lambda = \frac{h}{mv}\\ \\\lambda = \frac{6.626*10^{-34} }{(9.1*10^{-31})( 8.99*10^{5} )}\\\\\lambda = 8.10*10^{-10} \ m\\\\\lambda = 0.81 \ nm

Therefore, the shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

7 0
3 years ago
Raw data often appears in published scientific journals. Please select the best answer from the choices provided T F
Hatshy [7]

This statement is false

5 0
3 years ago
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