Average acceleration over a time interval lasting
is

where
is the difference in the jet's final and initial velocities. It's coming to a rest, so

so the average acceleration has magnitude 8.9 m/s^2 and is pointing West (the direction opposite the jet's movement, which should make sense because the jet is slowing down).
Theoretically, the light ray will not change direction. The center of a lens is called the optical center. If the ray of light hits the lens even just a little bit off center, the light ray is refracted. Refraction happens when the incident and exit angles of the ray are different. The optical center is guaranteed to not have any difference in angle, which allows the light ray to pass through directly without changing direction.
(1) The wavelength of the wave is 1.164 m.
(2) The velocity of the wave is 23.7 m/s.
(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
<h3>
Wavelength of the wave</h3>
A general wave equation is given as;
y(x, t) = A sin(Kx - ωt)
<h3>Velocity of the wave</h3>
v = ω/K
From the given wave equation, we have,
y(x, t) = 0.048 sin(5.4x - 128t)
v = ω/K
where;
- ω corresponds to 128
- k corresponds to 5.4
v = 128/5.4
v = 23.7 m/s
<h3>Wavelength of the wave</h3>
λ = 2π/K
λ = (2π)/(5.4)
λ = 1.164 m
<h3>Maximum speed of the wave</h3>
v(max) = Aω
where;
- A is amplitude of the wave
- ω is angular speed of the wave
v(max) = (0.048)(128)
v(max) = 6.14 m/s
Thus, the wavelength of the wave is 1.164 m.
The velocity of the wave is 23.7 m/s.
The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
Learn more about wavelength here: brainly.com/question/10728818
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The answer is to this question D
There's no such thing as "stationary in space". But if the distance
between the Earth and some stars is not changing, then (A) w<span>avelengths
measured here would match the actual wavelengths emitted from these
stars. </span><span>
</span><span>If a star is moving toward us in space, then (A) Wavelengths measured
would be shorter than the actual wavelengths emitted from that star.
</span>In order to decide what's actually happening, and how that star is moving,
the trick is: How do we know the actual wavelengths the star emitted ?