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Marta_Voda [28]
3 years ago
15

for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. ex

plain.​
Physics
1 answer:
AleksandrR [38]3 years ago
6 0
<h3><u>Answer</u></h3>

  • Distance is equal to the Total Distance covered by a body, from the initial till the final point.

  • Displacement is equal to the shortest distance between two points.

  • So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.

  • This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path
<h3>━━━━━━━━━━━━━━</h3>

<h3><u>Know </u><u>More</u></h3>

☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

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3 years ago
The weight of a body is 600 N. What is the mass of the body on the surface of the earth?​
mamaluj [8]

Explanation:

soln,

weight=600N

mass=?

gravity=9.8 m/s²

now,

  • mass=weight/gravity
  • mass=600/9.8
  • mass=61.22kg

hope it helps.

<h2>stay safe healthy and happy.</h2>
7 0
3 years ago
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If the resistance in a circuit remains constant, what happens to the electric power when the current increases?
bearhunter [10]

If the resistance in a circuit remains constant and the current increases, then the power will increase. <em>(A)</em>

In fact, it'll increase as fast as the <em><u>square</u></em> of the current !  Like, if the current somehow increases to 3 times as much, the circuit will start using <u><em>9 times</em></u> as much power as it did before.

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In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The
Naya [18.7K]

Answer:

0.615 m

Explanation:

We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, <em>u</em> = 0.00 m/s

Distance, <em>s</em> = 4.19 m

Time, <em>t</em> = 0.601 s

We use the equation

s = ut+\frac{1}{2}at^2

With <em>u</em> = 0.00 m/s,

s = \frac{1}{2}at^2

a = \dfrac{2s}{t^2}

a = \dfrac{2\times4.19\text{ m}}{(0.601\text{ s})^2} = 23.2\text{ m/s}^2

The force is

F = (13.1\text{ kg})(23.2\text{ m/s}^2) = 303.92 \text{ N}

From Hooke's law, the extension, <em>e</em>, of a string is given by

e = \dfrac{F}{k}

where <em>k</em> is the spring constant.

Hence,

e = \dfrac{303.92\text{ N}}{494\text{ N/m}} = 0.615\text{ m}

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