We know that there is 1 mole of Mn for every 1 mole of
KMnO4, therefore the molarity of Mn is similar with KMnO4:
Mn = 0.00300 M
Molar mass of Mn is 54.94 g / mol. Molarity (M) is moles /
L, therefore:
Mn = (0.00300 moles / L) * (54.94 g / mol) * (1000 mg / g)
<span>Mn = 164.82 mg / L = 164.82 ppm</span>
Answer:
a. Interference patterns are observed when a wave passes through a barrier with two slits
Explanation:
Interference is a situation where two waves superimpose to form a new wave of a different amplitude. This amplitude can be greater, same or lower.
the diagram attached below shows the movement of a wave through a barrier with two slits.
you can notice the portions of the wave that overlap. This overlapping of waves is the interference.
Thus, option A is correct.
The other options however, are not correct. as shown below:
Option B is wrong as waves exhibit diffraction <em>(it is diffraction of the light wave that produces the rainbows we see in the sky)</em>
Option C is wrong as waves do not travel straight through slits always.
Option D is wrong as waves can also interfere constructively and destructively.
Answer:
0.895V
Explanation:
The emf of an electrochemical cell is obtained from the Nernst equation as shown in the images attached. The emf of an electrochemical cell is read from voltmeter in the circuit. The Nernst equation is used to obtain the emf of cell when it is not operated under standard conditions. That is the concentration of solutions is not 1M, temperature is not 25oc and pressure (for gases is not 1ATM)
Answer:
8 mol
Explanation:
Step 1: Calculate the mass of PtCl₄ in the sample
10.00 grams of a sample of hydrated PtCl₄ are heated and lose 3.00 g of water. The mass of PtCl₄ is:
mPtCl₄ = 10.00 g - 3.00 g = 7.00 g
Step 2: Calculate the moles corresponding to 7.00 g of PtCl₄ and 3.00 g of H₂O
The molar mass of PtCl₄ is 336.9 g/mol.
7.00 g × 1 mol/336.9 g = 0.0208 mol
The molar mass of H₂O is 18.02 g/mol.
3.00 g × 1 mol/18.02 g = 0.166 mol
The molar ratio of H₂O to PtCl₄ is:
0.166 mol H₂O/0.0208 mol PtCl₄ ≈ 8 mol H₂O/ 1 mol PtCl₄