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3 years ago

Is that rational or irrational

Mathematics

1 answer:

creativ13 [48]3 years ago

3 0

Irrational

We know that pi is irrational (we can’t express it as a ratio of two numbers), and we are multiplying it by a rational number (-2). However -2 lots of something with infinite digits, will still have infinite digits, therefore it is irrational.

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I need help ASAP thank you

PIT_PIT [208]

Answer:

Step-by-step explanation:

every single graph is asimethrical because they have no trend.

4 0

3 years ago

Willing to give brainliest to the best answer! Please show your work! Need help with these 3 problems ASAP!

vampirchik [111]

Answer:

5:05

Step-by-step explanation:

3:30 + 1 hour = 4:30

4:30 + 35 mins = 5:05 pm

5 days per 1 gallon, 30 days for :

30/5 = 6

500/50 = 10

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3 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$