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Hunter-Best [27]
3 years ago
13

Did Lydia make an all-or-nothing or a marginal decision while spending her money? Justify your response.​

Physics
1 answer:
defon3 years ago
5 0

Answer:

Lydia made a marginal decision because she is trying to save for her collage by spending less, she will have some money left over after paying for her necessary to go to her college tuition.

Explanation:

She saved part of it for her college tuition and spent the remainder for the prom dress, car insurance, and birthday gift.

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Define the term DNA​
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Answer:

It is the carrier of genetic information.

4 0
3 years ago
Read 2 more answers
A point charge, Q1 = -4.2 μC, is located at the origin. A rod of length L = 0.35 m is located along the x-axis with the near sid
igor_vitrenko [27]

Answer:

a) attractiva, b) dF = k \frac{Q_1 \ dQ_2}{dx}, c)  F = k Q_1 \frac{Q_2}{d \ (d+L)}, d) F = -1.09 N

Explanation:

a) q1 is negative and the charge of the bar is positive therefore the force is attractive

b) For this exercise we use Coulomb's law, where we assume a card dQ₂ at a distance x

           dF = k \frac{Q_1 \ dQ_2}{dx}

where k is a constant, Q₁ the charge at the origin, x the distance

c) To find the total force we must integrate from the beginning of the bar at x = d to the end point of the bar x = d + L

         ∫ dF = k \ Q_1 \int\limits^{d+L}_d     {\frac{1}{x^2} } \, dQ_2

as they indicate that the load on the bar is uniformly distributed, we use the concept of linear density

          λ = dQ₂ / dx

          DQ₂ = λ dx

we substitute

         F = k \ Q_1 \lambda \int\limits^{d+L}_d  \, \frac{dx}{x^2}

         F = k Q1 λ (-\frac{1}{x})  

we evaluate the integral

        F = k Q₁ λ (- \frac{1}{d+L} + \frac{1}{d} )

        F = k Q₁ λ  ( \frac{L}{d \ (d+L)})

we change the linear density by its value

      λ = Q2 / L

       F = k Q_1 \frac{Q_2}{d \ (d+L)}

d) we calculate the magnitude of F

       F =9 10⁹ (-4.2 10⁻⁶)   \frac{10.4 10x^{-6} }{0.45 ( 0.45 +0.35)}

       F = -1.09 N

the sign indicates that the force is attractive

3 0
3 years ago
I don't really need this question answered, I just need someone to help explain to me what it's asking me. To me, it's worded ve
Evgen [1.6K]
Technically it’s asking what will happen to the skaters height it will rise to (the skaters highest point) if you change the initial height. Is this what you needed?
8 0
3 years ago
And air rifle pellet of mass 2 g Is fired into a block of modelling clay mounted on a model railway track. The trunk and modelli
Anna007 [38]

Answer:

0.0816 kgm/s

Explanation:

From the question,

Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.

P =(M+m)u...................... Equation 1

Where P =  initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck

Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg

Substitute these values into equation 1

P = (0.002+0.1)0.8

P = (0.102)0.8

P = 0.0816 kgm/s

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3 years ago
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