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Evgesh-ka [11]
2 years ago
12

Saturn orbits the Sun at more than 50% of the speed of Mars true or false​

Physics
1 answer:
ziro4ka [17]2 years ago
7 0

Answer:

false

Explanation:

the planet saturn rotates around the sun at 21,637mph

the planet mars rotates around the sun at 53,979mph

half the speed of mars is 26,989.5mph

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SUPPOSE THAT YOURE FACING A STRAIGHT CURRENT CARRYING CONDUCTOR, AND the current isfowing towards you. The lines of magnetic for
enot [183]
According to the right hand grip rule; if you point your right thumb in the direction of the current flow and curl your fingers around the current carrying conductor, the fingers will point in the direction of the circular magnetic field around the conductor. Therefore,if the the current carrying carrying conductor is held with the current flowing towards you, using right hand grip rule the lines of magnetic field will act towards a counterclockwise direction or anticlockwise direction.
7 0
3 years ago
Which of the following would increase the output force of a lever?
Vedmedyk [2.9K]
A. Increase the distance between the effort and the fulcrum
5 0
3 years ago
For a railgun, determine the current required to accelerate a 1000kg space vehicle to earths escape velocity on 10km of track wi
Troyanec [42]

Answer:

the current is 15.68 × 10^{5} A

Explanation:

mass = 1000 kg

magnetic fied = 2T

rail separation = 2m

escape velocity is 11.2km/s  = 11.2 × 10^{3} m/s

distance = 10 km = 10^{4} m

to find out

determine the current

solution

we know force F = I×L×B

here I is current and L is rail separation and B is magnetic field

so F = I ×2×2  = 4 I

so

acceleration is a = \frac{F}{mass}

a =  \frac{4I}{1000} m/s²

so equation of motion

v²-u² = 2 a S

here u is initial velocity and S is distance and a is acceleration and v is final velocity

11.2 × 10^{3} - 0 = 2×  \frac{4I}{1000} × 10^{4}

solve we get I

I = 15.68 × 10^{5} A

so the current is 15.68 × 10^{5} A

4 0
3 years ago
When being unloaded from a moving truck, a 16.0- kilogram suitcase is placed on a flat ramp inclined at 40.0 o. When released fr
9966 [12]

Answer:

0.65812

Explanation:

m = Mass of suitcase = 16 kg

\theta = Incline angle = 40°

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration of the block = 1.36 m/s²

f = Frictional force

The normal force is given by

N=mgcos\theta

In x direction

mgsin\theta-f=ma\\\Rightarrow f=mgsin\theta-ma\\\Rightarrow f=16\times 9.81\times sin40-16\times 1.36\\\Rightarrow f=79.13194\ N

Frictional force is given by

f=\mu N=\mu mgcos\theta\\\Rightarrow \mu=\dfrac{f}{mgcos\theta}\\\Rightarrow \mu=\dfrac{79.13194}{16\times 9.81\times cos40}\\\Rightarrow \mu=0.65812

The coefficient of kinetic friction between the suitcase and the ramp is 0.65812

8 0
3 years ago
A coil lies flat on a tabletop in a region where the magnetic field vector points straight up. The magnetic field vanishes sudde
Mademuasel [1]

Answer:

Option B - The induced current flows counter-clockwise.

Explanation:

Faraday's law of electromagnetic induction states that whenever a conductor is placed in a changing magnetic field, an electromotive force is induced and that if the conductor circuit is closed, a current is induced which is the induced current. The magnitude of the EMF induced in the coil is therefore proportional to the rate of change of magnetic flux throughout the coil.

Meanwhile, the direction of the induced current is given by Lenz's law which states that the direction of the induced current will oppose the change in electromagnetic force that produced that current.

Since the magnetic field points upwards, the induced current will move in a direction to the left which is counterclockwise

6 0
4 years ago
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