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elixir [45]
3 years ago
12

Helppppppppppppppp.......

Physics
1 answer:
kow [346]3 years ago
8 0

Answer:

9013 m/s

Explanation:

hope it helped!!!

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At what altitude the value of ‘g’ would become one fourth (¼)of the surface of the earth?
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Answer:

Explanation:

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dividing

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So at height equal to radius of the earth , acceleration due to gravity becomes 1 /4 of value on the surface of the earth .

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In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot
posledela

We use the equations of motion,

v = u + at                                               (A)

v^{2} = u^{2} + 2as                                (B)

Here, v is final velocity of the body, u is initial velocity of the body, a is the acceleration of the body, t is the time taken in the motion and s is distance traveled by the body.

Given u = 8 \ m/s, v = 40 \ m/s and t = 3.33 \times 10^{-2} \ s.

So, from equation (A)

40 \ m/s = 8 \ m/s + a ( 3.33 \times 10^{-2 } \ s) \\\\ a =  \frac{32 \ m/s}{3.33\times 10^{-2 } \ s  }  = 9.6 \times 10^{2} \ m/s^2

Now from the  equation (B),

(40 \ m/s)^2 = (8 \ m/s)^2 + 2 (9.6 \times 10^{2} m/s^2) \times s  \\\\ s = \frac{(40 \ m/s)^2-(8 \ m/s)^2}{2 (9.6 \times 10^{2} m/s^2} = 0.8 \ m

Thus, the distance over which the puck accelerates is 0.8 m.

6 0
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