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xxTIMURxx [149]
3 years ago
9

Find the mode of the following set of data.

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

13, 11, 4, 5, 6, 9, 10, 12, 15, 16

put the numbers from smallest to greatest

4,5,6,9,10,11,12,13,15,16

Mode means the popular number. The number that comes up a lot.

Answer: No mode because none of the numbers appear more than one.

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At which value(s) of x does the graph of the function F(x) have a vertical asymptote? Check all that apply.
Mars2501 [29]

Answer:

-2 is the only correct answer

4 0
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Write an expression to represent:<br> Three more than the product of two and a number xxx.
vesna_86 [32]
(2x)+3 is the correct answer. Please mark BRAINLIEST
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3 years ago
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Anumeha is mowing lawns for a summer job. For every mowing job, she charges an initial fee of $ 10 $10dollar sign, 10 plus a con
slavikrds [6]

Answer:

F(t) = 10 + 5(t)

Step-by-step explanation:

The complete question is as follows;

Anumeha is mowing lawns for a summer job. for every mowing job, she charges an initial fee of \$10$10dollar sign, 10 plus a constant fee for each hour of work. her fee for a 555-hour job, for instance, is \$35$35dollar sign, 35. let f(t)f(t)f, left parenthesis, t, right parenthesis denote anumeha's fee for a single job fff (measured in dollars) as a function of the number of hours ttt it took her to complete it. write the function's formula.

Solution

We are interested in writing the function F(t) formula for the fee charged by Anumeha per job.

Now, the key to writing this function is knowing exactly the constant fee she charges on the job.

We were told that she got $35 for a 5 hour job.

Thus, the constant amount charged is as follows;

Since it’s $10 as initial fee and the constant fee is per hour;

35 = 10 + 5(x)

where x is the constant fee per hour

35 = 10 + 5x

5x = 35-10

5x = 25

x = 25/5

x = $5

This mess that she charges a constant fee of $5 per hour

So we can write the equation now.

F(t) = 10 + 5(t)

where t represents the number of hours she spent on the job

6 0
3 years ago
A scooter manufacturer makes two types of scooters: the Go-go, which sells for $3,200 and the Whip sells for $5,000. Both models
garik1379 [7]
Let the number of Go-go scooter to be produced be x and that of Whip scooter y, then
Maximize: R = 3200x + 5000y
subject to:
x + y ≤ 120
3x + 6y ≤ 600
The corner points of the constraints are (0, 0), (0, 100), (40, 80), (120, 0)
For (0, 0): R = 0
For (0, 100): R = 3200(0) + 5000(100) = 500,000
For (40, 80): R = 3200(40) + 5000(80) = 528,000
For (120, 0): R = 3200(120) + 5000(0) = 384,000

Therefore, for maximum revenue, they should produce 40 Go-go scooters and 80 Whip scooters.
4 0
4 years ago
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You answer should say: Car _ by __ km/hr (Use care in answering!)
Lina20 [59]

Answer:

Car B by 20km/hr

Step-by-step explanation:

well, we first calculate the speeds of both cars. there is an allocated dot along the 6 hour mark for the line graph of both cars. hence, using a time of 6 hours, we use their respective distances to produce an answer. car a has travelled 360 km while car v has travelled 480 km.

hence:

speed of car b = 480/6 = 80

speed of car a = 360/6 = 60

8 0
4 years ago
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