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3 years ago

What do you think the disadvantages of nuclear energy are nabilne fa

Physics

1 answer:

SpyIntel [72]3 years ago

7 0

Answer:

1 . Environmental impact. Although nuclear power plants release zero carbon emissions, nuclear power still has a substantial impact on the environment, mainly through mining and water discharge. ...

2. Water intensive. ...

3.Risk of nuclear accidents. ...

4.Radioactive waste. ...

5.Non-renewable.

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Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelera

svetlana [45]

Answer:

(a) Fₓ = 0 N

$F_y$ = 9.08 N

(b)

(a) Fₓ = 0 N

$F_y$ = 9.08 N

Fₓ = 9.08 N

Explanation:

The magnitude of the force will remain the same in each case, which is given as follows:

F = ma (Newton's Second Law)

where,

F = force = ?

m = mass = 4.54 kg

a = acceleration = 2 m/s²

Therefore,

F = (4.54 kg)(2 m/s²)

F = 9.08 N

Now, we come to each scenario:

(a)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

Fₓ = 0 N

For upward direction the force will be positive:

$F_y$ = 9.08 N

(b)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

Fₓ = 0 N

For upward direction the force will be negative:

$F_y$ = - 9.08 N

(c)

Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:

$F_y$ = 0 N

Fₓ = 9.08 N

3 0

3 years ago

The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in

N76 [4]

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

$d=\frac{v^2}{g}sin 2\theta$

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

$\theta$ is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

$\theta=45^{\circ}$ is the angle

Solving for v, we find the speed of the projectile:

$v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s$

7 0

3 years ago

5)A 0.50 kg hockey puck is at rest on ice when you hit it with a hockey stick, applying a force of 100 N for

mojhsa [17]

Answer:

F t = m Δv impulse delivered = change in momentum

Δv = 100 * .1 / .5 = 20 m/s original speed of puck

KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J initial KE of puck

E = μ m g d energy lost by puck

Ff = μ m g = m a deceleration of puck due to friction

a = μ g = 9.8 * .2 = 1.96 m/s^2

v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s speed of puck on striking box

m v2 = M V conservation of momentum when puck strikes box

V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s speed of box after collision

KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J KE of box after collision

KE = μ M g d energy lost by box in sliding distance d

d = 23.3 / (.3 * .8 * 9.8) = 9.91 m distance box slides

7 0

2 years ago

An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-

Nataliya [291]

Answer:

a) 1.875 volts

b) 5.86 W

Explanation:

Given data:

transmission line resistance = 0.30/cable

power of the generator = 250 kW

if Vt = 80 kV

a) Determine the decrease V along the transmission line

Rms current in cable = P / Vt = 250 / 80 = 3.125 amps

hence the rms voltage drop ( Δrmsvoltage )

Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 = 1.875 volts

b) Determine the rate Pd at which energy is dissipated in line as thermal energy

Pd = $I^2rms*R$

= 3.125^2 * 2* 0.30 = 5.86 W

3 0

3 years ago

A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−

Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ .

Explanation:

Given that,

The actual wavelength of the hydrogen atom, $\lambda_a=5.13\times 10^{-7}\ m$

A hydrogen atom in a galaxy moving with a speed of, $v=6.65\times 10^6\ m/s$

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

$v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}$

$\lambda_o$ is the observed wavelength

$\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m$

So, the observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ . Hence, this is the required solution.

8 0

3 years ago

What do you think the disadvantages of nuclear energy are nabilne fa​

What do you think the disadvantages of nuclear energy are nabilne fa