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Arada [10]
3 years ago
9

A bowling ball weighing 71.7 N is attached to the ceiling by a rope of length 3.73 m . The ball is pulled to one side and releas

ed; it then swings back and forth as a pendulum. As the rope swings through the vertical, the speed of the bowling ball is 4.60 m/s. At this instant, what are:
a. the acceleration of the bowling ball, in magnitude and direction
b. the tension in the rope?
Physics
1 answer:
vekshin13 years ago
4 0

Answer:

A) a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) T = 113.2 N

Explanation:

A) We are given;

Weight of bowling ball; W = 71.7 N

Speed; v = 4.6 m/s

Rope length; r = 3.73 m

Now, formula for the centripetal acceleration is;

a = v²/r

Thus; a = 4.6²/3.73

a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) since weight is 71.7 N, it means that;

Mass = weight/acceleration = 71.7/9.8

Mass(m) = 7.316 kg

Thus,

Centripetal force is;

F_cent = 7.316 × 5.673

F_cent = 41.5 N

Thus, Tension in the rope is;

T = W + F_cent

T = 71.7 + 41.5

T = 113.2 N

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In a video game, a flying coconut moves at a constant velocity of 20 meters/second. The coconut hits an obstacle and moves in th
qwelly [4]
Change in velocity = Final velocity - Initial velocity

Initial velocity = 20 m/s
Final velocity = 10 m/s

Change in velocity = 10 - 20 = -10m/s

Correct option B

Hope This Helps You!
4 0
3 years ago
A 4.8-kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t=0 s, the blo
garri49 [273]

Answer:

E) 80 N/m

Explanation:

Given;

mass of the block, m = 4.8 kg

displacement of the block, x = -0.5 m

velocity of the block, v = -0.8 m/s

acceleration of the block, a = 8.3 m/s²

From Newton's second law of motion;

F = ma

Also, from Hook's law;

F = -Kx

where;

k is the force constant

Thus, ma = -kx

k = -ma/x

k = -(4.8 x 8.3) / (-0.5)

k = 79.7 N/m

k ≅ 80 N/m

Therefore, the force constant of the spring is closest to 80 N/m

4 0
3 years ago
A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of
sasho [114]

Answer:

a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m

b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m

Explanation:

(a) Radiowave wavelength= λ = c/f

As we know, Radiowave speed in the air = c = 3 x 10^8 m/s

f = frequency = 604 kHz = 604 x 10^3 Hz

Hence, wavelength = (3x10^8/604x10^3) m

λ = 496.69 m

So the height of the antenna BROADCASTING AT 604 kHz =  λ /4 = (496.69/4) m

= 124.17 m

(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz  (1kHZ = 1000 Hz)

Hence, wavelength =  λ = (3 x 10^8/1710 x 10^3) m

 λ= 175.44 m

So, height of the antenna =  λ /4 = (175.44/4) m

= 43.86 m  

5 0
3 years ago
Why is the sum of forces/net force less than the applied force? Think about the direction of the forces in your answer
Reil [10]

Answer:

he same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem

Explanation:

When there are several applied forces, if they are all in the same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem, so which the resulting dowry is less than the sum of the magnitudes.

Let's carry out an example with two forces, F1 and F2 of equal magnitudes

if they are in the same direction

           F_total = F₁ + F₂ = 2 F

if they are at 90º

          F_total = \sqrt{F_1^2 + F_2^2}= \sqrt{2}  \ F

if they are at 180º

          F_total = F₁ -F₂ = 0

3 0
2 years ago
Please I need help on this one
Lisa [10]

lake effect snow is the correct answer

5 0
3 years ago
Read 2 more answers
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