1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arada [10]
3 years ago
9

A bowling ball weighing 71.7 N is attached to the ceiling by a rope of length 3.73 m . The ball is pulled to one side and releas

ed; it then swings back and forth as a pendulum. As the rope swings through the vertical, the speed of the bowling ball is 4.60 m/s. At this instant, what are:
a. the acceleration of the bowling ball, in magnitude and direction
b. the tension in the rope?
Physics
1 answer:
vekshin13 years ago
4 0

Answer:

A) a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) T = 113.2 N

Explanation:

A) We are given;

Weight of bowling ball; W = 71.7 N

Speed; v = 4.6 m/s

Rope length; r = 3.73 m

Now, formula for the centripetal acceleration is;

a = v²/r

Thus; a = 4.6²/3.73

a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) since weight is 71.7 N, it means that;

Mass = weight/acceleration = 71.7/9.8

Mass(m) = 7.316 kg

Thus,

Centripetal force is;

F_cent = 7.316 × 5.673

F_cent = 41.5 N

Thus, Tension in the rope is;

T = W + F_cent

T = 71.7 + 41.5

T = 113.2 N

You might be interested in
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
NARA [144]

The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².                                                                                      

When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:

v_{f_{r}} = v_{i_{r}} + at    

Where:                                                              

v_{f_{r}}: is the final velocity of the rocket

v_{i_{r}}: is the initial velocity of the rocket = 0

a: is the acceleration

t: is the time

After 4 seconds, the <u>final speed of the rocket</u> will be the <u>initial speed of the bolt</u>, so:                                              

v_{f_{r}} = v_{i_{b}} = at = 4a  

When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.        

The<u> initial height of the bolt</u> will be the <u>final height of the rocket</u>, and vice-versa. With this, we can take the final height of the bolt as zero.                        

y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a

Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:

y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2}

194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2}    

a = \frac{194.7}{33.2} = 5.86 m/s^{2}    

   

Therefore, the acceleration of the rocket is 5.68 m/s².

You can find another example of acceleration calculation here: brainly.com/question/24589208?referrer=searchResults

I hope it helps you!                                                                              

3 0
2 years ago
9.The force of gravity between two asteroids is 10,000 newtons (N).
MakcuM [25]

Answer:

F1 = G m1 m2 / R^2        force of attraction

F2 = G m1 m2 / (R/2)^2

F2 / F1 = 4       the force of gravity will be quadrupled

6 0
2 years ago
A satellite has a mass of 5832 kg and is in a circular orbit 4.13 × 105 m above the surface of a planet. The period of the orbit
elena55 [62]

Answer:

W = 28226.88 N

Explanation:

Given,

Mass of the satellite, m = 5832 Kg

Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m

The time period of the orbit, T = 1.9 h

                                            = 6840 s

The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

                             T = 2\pi \sqrt{\frac{(R+h)^{3} }{R^{2} g} }  second

Squaring the terms and solving it for 'g'

                             g = 4 π² \frac{(R+h)^{3} }{R^{2}T^{2}  }   m/s²

Substituting the values in the above equation

                   g = 4 π² \frac{(4.38X10^6+4.13X10^5)^{3} }{(4.38X10^6)^{2}X6840^{2}}  

                                    g = 4.84 m/s²      

Therefore, the weight

                                     w = m x g   newton

                                         = 5832 Kg x 4.84 m/s²

                                         = 28226.88 N

Hence, the weight of the satellite at the surface, W = 28226.88 N                

8 0
3 years ago
A camera lens with focal length f = 50 mm and maximum aperture f&gt;2
Brut [27]

Answer:

The minimum distance between two points on the  object that are barely resolved is 0.26 mm

The corresponding distance between the  image points = 0.0015 m

Explanation:

Given  

focal length f = 50 mm and maximum aperture f>2

s =  9.0 m

aperture = 25 mm = 25 *10^-3 m

Sin a = 1.22 *wavelength /D  

Substituting the given values, we get –  

Sin a = 1.22 *600 *10^-9 m /25 *10^-3 m

Sin a = 2.93 * 10 ^-5 rad

Now  

Y/9.0 m = 2.93 * 10 ^-5

Y = 2.64 *10^-4 m = 0.26 mm

Y’/50 *10^-3 = 2.93 * 10 ^-5  

Y’ = 0.0015 m

8 0
3 years ago
Car a runs a red light and broadsides car b, which is stopped and waiting to make a left turn. car a has a mass of 1,800kg. car
frez [133]

The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

mA vA + mB vB = m v

where, m is the mass in kg, v is the velocity in m/s

since m is the total mass, m = mA + mB, we can write the equation as:

mA vA + mB vB = (mA + mB) v

furthermore, car B was at a stop signal therefore vB = 0, hence

mA vA + 0 = (mA + mB) v

1800 (vA) = (1800 + 1500) (7.1 m/s)

<span>vA = 13.02 m/s</span>

7 0
3 years ago
Other questions:
  • The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t
    14·1 answer
  • Mike drove 70 km due west and then 100 km due east.
    8·1 answer
  • Which of the following would be an example of an uncontrolled experiment? The effect of salt and water being mixed at different
    10·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> What types of waves are Sound Waves?
    6·1 answer
  • The calorie count of a serving of food can be computed based on its composition of​ carbohydrate, fat, and protein. The calorie
    14·1 answer
  • A spherical balloon is being inflated. Find the rate of increase of the surface area (S = 4Ï€r2) with respect to the radius r wh
    15·1 answer
  • A square plate of copper with 47.0 cm sides has no net charge and is placed ina region of uniform electric field of 75.0 kN/C di
    15·1 answer
  • Definition: In any chemical process, matter is neither lost nor gained.
    14·1 answer
  • What can cause a magnetic domain to form?
    15·2 answers
  • An alarm clock is dropped off the edge of a tall building. You, standing directly under it, hear a tone of 1350 Hz coming from t
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!