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3 years ago

Satelite communication is only possible using

Physics

2 answers:

Paha777 [63]3 years ago

7 0

the correct answer is B) digital transmission

zimovet [89]3 years ago

6 0

None of the choices is correct.

Satellite communication is quite effective using either analog OR digital transmission.

Sound can't be used for satellite communication at all. (There's no medium to carry the sound to or from the satellite, and if there were, then the round-trip up and down through a geostationary satellite would take at least a minute at the sea-level speed of sound.)

Cellular devices can work but aren't required.

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Electromagnetic waves can behave like particles

Ilya [14]

Yes they can. Uh-huh. Indubitably. That's right, Vanessa. It's true.

A better way to say it might be:

Electromagnetic radiation can behave like waves AND like particles.

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3 years ago

A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.200 fg (where a femtogra

andriy [413]

Answer:

58.22pm

Explanation:

Look up attached file

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3 years ago

A pesticide kills insects by disabling the ribosomes in their cells.

Stolb23 [73]

Answer:

cell division

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3 years ago

Read 2 more answers

Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planc

Viefleur [7K]

In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
   E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

   E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

      = <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>

5 0

3 years ago

3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La

jok3333 [9.3K]

Answer:

f1 = 12.90 Hz

Explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

$f_n=\frac{n}{2L}\sqrt{\frac{T}{M/L}}$

$f_1=\frac{1}{2L}\sqrt{\frac{T}{M/L}}$ ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

$f_1=\frac{1}{2(0.6m)}\sqrt{\frac{20N}{0.05kg/0.6m}}=12.90\ Hz$

Hence, the first harmonic has a frequency of 12.90 Hz

4 0

3 years ago