Answer:
Explanation:
Given that,
Frequency f = 5 kHz = 5000Hz
Voltage V=45V
Current In inductor I = 65mA
I = 65 × 10^-3 = 0.065A
We want to find inductance L
We know that the reactive inductance cam be given as
XL = 2πFL
Where
XL is reactive inductance
F is frequency
L is inductance
Then,
L = XL/2πF
From ohms law
V = IR
We can calculate the receive reactance of the inductor
V = I•XL
Then, XL = V/I
XL = 45/0.065
XL = 692.31 ohms
Then,
L = XL/2πF
L = 692.31/(2π×5000)
L = 0.02204 H
Then, L = 22.04 mH
The inductance of the inductor is 22.04mH
Answer:
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Answer:
Explanation:
We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .
f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .
f will be lowest when v₀ is highest .
velocity of observer is highest when he is at the equilibrium position or at middle point .
So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .
Complete Question
An L-C circuit has an inductance of 0.350 H and a capacitance of 0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .
What is the maximum energy
stored in the capacitor at any time during the current oscillations?
Express your answer in joules.
Answer:
The value is 
Explanation:
From the question we are told that
The inductance is 
The capacitance is 
The current is 
Generally the maximum energy is mathematically represented as

=> 
=> 
B is the answer!!!!!!!!!!!!!